Python: Compute the sum of digits of each number of a given list
Python List: Exercise - 146 with Solution
Write a Python program to compute the sum of digits of each number in a given list.
Sample Solution:
Python Code:
def sum_of_digits(nums):
return sum(int(el) for n in nums for el in str(n) if el.isdigit())
nums = [10,2,56]
print("Original tuple: ")
print(nums)
print("Sum of digits of each number of the said list of integers:")
print(sum_of_digits(nums))
nums = [10,20,4,5,'b',70,'a']
print("\nOriginal tuple: ")
print(nums)
print("Sum of digits of each number of the said list of integers:")
print(sum_of_digits(nums))
nums = [10,20,-4,5,-70]
print("\nOriginal tuple: ")
print(nums)
print("Sum of digits of each number of the said list of integers:")
print(sum_of_digits(nums))
Sample Output:
Original tuple: [10, 2, 56] Sum of digits of each number of the said list of integers: 14 Original tuple: [10, 20, 4, 5, 'b', 70, 'a'] Sum of digits of each number of the said list of integers: 19 Original tuple: [10, 20, -4, 5, -70] Sum of digits of each number of the said list of integers: 19
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Python: Tips of the Day
Given a predicate function, fn, and a prop string, this curried function will then take an object to inspect by calling the property and passing it to the predicate:
Example:
def tips_check_prop(fn, prop): return lambda obj: fn(obj[prop]) check_age = tips_check_prop(lambda x: x >= 25, 'age') user = {'name': 'Owen', 'age': 25} print(check_age(user))
Output:
True
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