Python: Check if a given element occurs at least n times in a list
Python List: Exercise - 153 with Solution
Write a Python program to check if a given element occurs at least n times in a list.
def check_element_in_list(lst, x, n): t = 0 try: for _ in range(n): t = lst.index(x, t) + 1 return True except ValueError: return False nums = [0,1,3,5,0,3,4,5,0,8,0,3,6,0,3,1,1,0] print("Original list:") print(nums) x = 3 n = 4 print("\nCheck if",x,"occurs at least",n,"times in a list:") print(check_element_in_list(nums,x,n)) x = 0 n = 5 print("\nCheck if",x,"occurs at least",n,"times in a list:") print(check_element_in_list(nums,x,n)) x = 8 n = 3 print("\nCheck if",x,"occurs at least",n,"times in a list:") print(check_element_in_list(nums,x,n))
Original list: [0, 1, 3, 5, 0, 3, 4, 5, 0, 8, 0, 3, 6, 0, 3, 1, 1, 0] Check if 3 occurs at least 4 times in a list: True Check if 0 occurs at least 5 times in a list: True Check if 8 occurs at least 3 times in a list: False
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Python: Tips of the Day
When we speak of division we normally mean (/) float division operator, this will give a precise result in float format with decimals.
For a rounded integer result there is (//) floor division operator in Python. Floor division will only give integer results that are round numbers.
print(1000 // 300) print(1000 / 300)
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