Python: Interleave multiple lists of different lengths
Python List: Exercise - 157 with Solution
Write a Python program to interleave lists of varying lengths.
Sample Solution:
Python Code:
def interleave_diff_len_lists(list1, list2, list3, list4):
result = []
l1 = len(list1)
l2 = len(list2)
l3 = len(list3)
l4 = len(list4)
for i in range(max(l1, l2, l3, l4)):
if i < l1:
result.append(list1[i])
if i < l2:
result.append(list2[i])
if i < l3:
result.append(list3[i])
if i < l4:
result.append(list4[i])
return result
nums1 = [2, 4, 7, 0, 5, 8]
nums2 = [2, 5, 8]
nums3 = [0, 1]
nums4 = [3, 3, -1, 7]
print("\nOriginal lists:")
print(nums1)
print(nums2)
print(nums3)
print(nums4)
print("\nInterleave said lists of different lengths:")
print(interleave_diff_len_lists(nums1, nums2, nums3, nums4))
Sample Output:
Original lists: [2, 4, 7, 0, 5, 8] [2, 5, 8] [0, 1] [3, 3, -1, 7] Interleave said lists of different lengths: [2, 2, 0, 3, 4, 5, 1, 3, 7, 8, -1, 0, 7, 5, 8]
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Python: Tips of the Day
Given a predicate function, fn, and a prop string, this curried function will then take an object to inspect by calling the property and passing it to the predicate:
Example:
def tips_check_prop(fn, prop): return lambda obj: fn(obj[prop]) check_age = tips_check_prop(lambda x: x >= 25, 'age') user = {'name': 'Owen', 'age': 25} print(check_age(user))
Output:
True
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