Python: Index of the first element which is greater than a specified element

Python List: Exercise - 163 with Solution

Write a Python program to get the index of the first element that is greater than a specified element.

Sample Solution:

Python Code:

def first_index(l1, n):
    return next(a[0] for a in enumerate(l1) if a[1] > n)
 
nums = [12,45,23,67,78,90,100,76,38,62,73,29,83]
print("Original list:")
print(nums)
n = 73
print("\nIndex of the first element which is greater than",n,"in the said list:")
print(first_index(nums,n))
n = 21
print("\nIndex of the first element which is greater than",n,"in the said list:")
print(first_index(nums,n))
n = 80
print("\nIndex of the first element which is greater than",n,"in the said list:")
print(first_index(nums,n))
n = 55
print("\nIndex of the first element which is greater than",n,"in the said list:")
print(first_index(nums,n))

Sample Output:

Original list:
[12, 45, 23, 67, 78, 90, 100, 76, 38, 62, 73, 29, 83]

Index of the first element which is greater than 73 in the said list:
4

Index of the first element which is greater than 21 in the said list:
1

Index of the first element which is greater than 80 in the said list:
5

Index of the first element which is greater than 55 in the said list:
3

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