# Python: Compute the average of n^{th} elements in a given list of lists with different lengths

## Python List: Exercise - 197 with Solution

Write a Python program to compute the average of the n-th element in a given list of lists with different lengths.

**Visual Presentation: **

**Sample Solution:**

**Python Code:**

```
# Import the 'itertools' module as 'it' for convenience.
import itertools as it
# Create a list of lists 'nums' with varying lengths.
nums = [[0, 1, 2],
[2, 3, 4],
[3, 4, 5, 6],
[7, 8, 9, 10, 11],
[12, 13, 14]]
# Print a message indicating the original list of lists.
print("Original list:")
# Print the original 'nums' list.
print(nums)
# Define a function 'get_avg' that calculates the average of a list, ignoring 'None' values.
def get_avg(x):
# Remove 'None' values from the list 'x'.
x = [i for i in x if i is not None]
# Calculate the average of the remaining values.
return sum(x, 0.0) / len(x)
# Use the 'zip_longest' function from 'itertools' to iterate over the 'nums' lists and calculate the average.
result = map(get_avg, it.zip_longest(*nums))
# Print a message indicating the average of the n-th elements in the list of lists with different lengths.
print("\nAverage of n-th elements in the said list of lists with different lengths:")
# Convert the 'result' to a list and print it.
print(list(result))
```

Sample Output:

Original list: [[0, 1, 2], [2, 3, 4], [3, 4, 5, 6], [7, 8, 9, 10, 11], [12, 13, 14]] Average of n-th elements in the said list of lists with different lengths: [4.8, 5.8, 6.8, 8.0, 11.0]

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