Python: Find the indexes of all None items in a given list
Python List: Exercise - 202 with Solution
Write a Python program to find the indexes of all None items in a given list.
Sample Solution:
Python Code:
def relative_order(lst):
result = [i for i in range(len(lst)) if lst[i] == None]
return result
nums = [1, None, 5, 4,None, 0, None, None]
print("Original list:")
print(nums)
print("\nIndexes of all None items of the list:")
print(relative_order(nums))
Sample Output:
Original list: [1, None, 5, 4, None, 0, None, None] Indexes of all None items of the list: [1, 4, 6, 7]
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Python: Tips of the Day
Given a predicate function, fn, and a prop string, this curried function will then take an object to inspect by calling the property and passing it to the predicate:
Example:
def tips_check_prop(fn, prop): return lambda obj: fn(obj[prop]) check_age = tips_check_prop(lambda x: x >= 25, 'age') user = {'name': 'Owen', 'age': 25} print(check_age(user))
Output:
True
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