Python: Change the position of every n-th value with the (n+1)th in a list
Python List: Exercise - 38 with Solution
Write a Python program to change the position of every n-th value to the (n+1)th in a list.
Sample Solution:-
Python Code:
from itertools import zip_longest, chain, tee
def replace2copy(lst):
lst1, lst2 = tee(iter(lst), 2)
return list(chain.from_iterable(zip_longest(lst[1::2], lst[::2])))
n = [0,1,2,3,4,5]
print(replace2copy(n))
Sample Output:
[1, 0, 3, 2, 5, 4]
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Python: Tips of the Day
Given a predicate function, fn, and a prop string, this curried function will then take an object to inspect by calling the property and passing it to the predicate:
Example:
def tips_check_prop(fn, prop):
return lambda obj: fn(obj[prop])
check_age = tips_check_prop(lambda x: x >= 25, 'age')
user = {'name': 'Owen', 'age': 25}
print(check_age(user))
Output:
True
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