﻿ Python: Change the position of every n-th value with the (n+1)th in a list - w3resource

# Python: Change the position of every n-th value with the (n+1)th in a list

## Python List: Exercise - 38 with Solution

Write a Python program to change the position of every n-th value to the (n+1)th in a list. Sample Solution:-

Python Code:

``````from itertools import zip_longest, chain, tee
def replace2copy(lst):
lst1, lst2 = tee(iter(lst), 2)
return list(chain.from_iterable(zip_longest(lst[1::2], lst[::2])))
n = [0,1,2,3,4,5]
print(replace2copy(n))
```
```

Sample Output:

```[1, 0, 3, 2, 5, 4]
```

Flowchart: ## Visualize Python code execution:

The following tool visualize what the computer is doing step-by-step as it executes the said program:

Python Code Editor:

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## Python: Tips of the Day

Given a predicate function, fn, and a prop string, this curried function will then take an object to inspect by calling the property and passing it to the predicate:

Example:

```def tips_check_prop(fn, prop):
return lambda obj: fn(obj[prop])
check_age = tips_check_prop(lambda x: x >= 25, 'age')
user = {'name': 'Owen', 'age': 25}

print(check_age(user))
```

Output:

```True
```

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