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Python: Change the position of every n-th value with the (n+1)th in a list

Python List: Exercise - 38 with Solution

Write a Python program to change the position of every n-th value to the (n+1)th in a list.

Python: Change the position of every n-th value with the (n+1)th in a list

Sample Solution:-

Python Code:

from itertools import zip_longest, chain, tee
def replace2copy(lst):
    lst1, lst2 = tee(iter(lst), 2)
    return list(chain.from_iterable(zip_longest(lst[1::2], lst[::2])))
n = [0,1,2,3,4,5]
print(replace2copy(n))

Sample Output:

[1, 0, 3, 2, 5, 4] 

Flowchart:

Flowchart: Change the position of every n-th value with the (n+1)th in a list

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Python Code Editor:

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Python: Tips of the Day

Given a predicate function, fn, and a prop string, this curried function will then take an object to inspect by calling the property and passing it to the predicate:

Example:

def tips_check_prop(fn, prop):
  return lambda obj: fn(obj[prop])
check_age = tips_check_prop(lambda x: x >= 25, 'age')
user = {'name': 'Owen', 'age': 25}

print(check_age(user))

Output:

True 

 





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