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Python: Find a tuple, the smallest second index value from a list of tuples

Python List: Exercise - 60 with Solution

Write a Python program to find a tuple, the smallest second index value from a list of tuples.

Sample Solution:-

Python Code:

x = [(4, 1), (1, 2), (6, 0)]
print(min(x, key=lambda n: (n[1], -n[0])))

Sample Output:

(6, 0) 

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Python List: Find a tuple, the smallest second index value from a list of tuples.

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Flowchart: Find a tuple, the smallest second index value from a list of tuples

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Python: Tips of the Day

Returns the symmetric difference between two lists, after applying the provided function to each list element of both

Example:

def tips_symmetric_difference_by(p, q, fn):
  _p, _q = set(map(fn, p)), set(map(fn, q))
  return [item for item in p if fn(item) not in _q] + [item for item in q if fn(item) not in _p]
from math import floor
print(tips_symmetric_difference_by([4.2, 2.4], [4.6, 6.8],floor))

Output:

[2.4, 6.8]