Python: Find a tuple, the smallest second index value from a list of tuples
Python List: Exercise - 60 with Solution
Write a Python program to find a tuple, the smallest second index value from a list of tuples.
x = [(4, 1), (1, 2), (6, 0)] print(min(x, key=lambda n: (n, -n)))
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Python: Tips of the Day
Returns the symmetric difference between two lists, after applying the provided function to each list element of both
def tips_symmetric_difference_by(p, q, fn): _p, _q = set(map(fn, p)), set(map(fn, q)) return [item for item in p if fn(item) not in _q] + [item for item in q if fn(item) not in _p] from math import floor print(tips_symmetric_difference_by([4.2, 2.4], [4.6, 6.8],floor))
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