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Python: Count number of unique lists within list

Python List: Exercise - 94 with Solution

Write a Python program to count the number of unique sublists within a given list.

Sample Solution:

Python Code:

def unique_sublists(input_list):
    result ={}
    for l in input_list: 
        result.setdefault(tuple(l), list()).append(1) 
    for a, b in result.items(): 
        result[a] = sum(b)
    return result

list1 = [[1, 3], [5, 7], [1, 3], [13, 15, 17], [5, 7], [9, 11]] 
print("Original list:")
print(list1)  
print("Number of unique lists of the said list:")
print(unique_sublists(list1)) 

color1 = [["green", "orange"], ["black"], ["green", "orange"], ["white"]]
print("\nOriginal list:")
print(color1)  
print("Number of unique lists of the said list:")
print(unique_sublists(color1))

Sample Output:

Original list:
[[1, 3], [5, 7], [1, 3], [13, 15, 17], [5, 7], [9, 11]]
Number of unique lists of the said list:
{(1, 3): 2, (5, 7): 2, (13, 15, 17): 1, (9, 11): 1}

Original list:
[['green', 'orange'], ['black'], ['green', 'orange'], ['white']]
Number of unique lists of the said list:
{('green', 'orange'): 2, ('black',): 1, ('white',): 1}

Pictorial Presentation:

Python List: Count number of unique lists within list.

Flowchart:

Flowchart: Count number of unique lists within list.

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Python Code Editor:

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Python: Tips of the Day

Given a predicate function, fn, and a prop string, this curried function will then take an object to inspect by calling the property and passing it to the predicate:

Example:

def tips_check_prop(fn, prop):
  return lambda obj: fn(obj[prop])
check_age = tips_check_prop(lambda x: x >= 25, 'age')
user = {'name': 'Owen', 'age': 25}

print(check_age(user))

Output:

True 

 





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