w3resource

NumPy: Average of every consecutive triplet of elements of a given array

NumPy: Array Object Exercise-157 with Solution

Write a NumPy program to create a new array which is the average of every consecutive triplet of elements of a given array.

Sample Solution:

Python Code:

import numpy as np
arr1 = np.array([1,2,3, 2,4,6, 1,2,12, 0,-12,6])
print("Original array:")
print(arr1)
result = np.mean(arr1.reshape(-1, 3), axis=1)
print("Average of every consecutive triplet of elements of the said array:")
print(result)

Sample Output:

Original array:
[  1   2   3   2   4   6   1   2  12   0 -12   6]
Average of every consecutive triplet of elements of the said array:
[ 2.  4.  5. -2.]

Pictorial Presentation:

NumPy: Average of every consecutive triplet of elements of a given array

Python Code Editor:

Have another way to solve this solution? Contribute your code (and comments) through Disqus.

Previous: Write a NumPy program to calculate averages without NaNs along a given array.
Next: Write a NumPy program to calculate average values of two given numpy arrays.

What is the difficulty level of this exercise?

Test your Python skills with w3resource's quiz



Python: Tips of the Day

Set comprehension:

>>> m = {x ** 2 for x in range(5)}
>>> m
{0, 1, 4, 9, 16}