NumPy: Construct an array by repeating
Repeat Array Entirely
Write a NumPy program to construct an array by repeating.
Sample array: [1, 2, 3, 4]
Pictorial Presentation:
Sample Solution:
Python Code:
# Importing the NumPy library with an alias 'np'
import numpy as np
# Creating an original array
a = [1, 2, 3, 4]
print("Original array")
print(a)
# Repeating the original array two times using np.tile
print("Repeating 2 times")
x = np.tile(a, 2)
print(x)
# Repeating the original array three times using np.tile
print("Repeating 3 times")
x = np.tile(a, 3)
print(x)
Sample Output:
Original array [1, 2, 3, 4] Repeating 2 times [1 2 3 4 1 2 3 4] Repeating 3 times [1 2 3 4 1 2 3 4 1 2 3 4]
Explanation:
In the above code -
a = [1, 2, 3, 4]: A list a is defined with four elements.
x = np.tile(a, 2): np.tile repeats the given list a 2 times along its first axis. In this case, a is repeated twice, creating a new NumPy array: [1, 2, 3, 4, 1, 2, 3, 4].
x = np.tile(a, 3): np.tile repeats the given list a 3 times along its first axis. In this case, a is repeated thrice, creating a new NumPy array: [1, 2, 3, 4, 1, 2, 3, 4, 1, 2, 3, 4].
For more Practice: Solve these Related Problems:
- Repeat a one-dimensional array using np.tile and validate that its shape is doubled or tripled as expected.
- Create a function to repeat an array and then reshape the repeated output into a matrix.
- Verify that the sum of a repeated array equals the original array’s sum multiplied by the number of repetitions.
- Repeat an array entirely and compare the result with manual concatenation of the original array.
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