NumPy: Find the nearest value from a given value in an array
NumPy: Random Exercise-9 with Solution
Write a NumPy program to find the nearest value from a given value in an array.
Sample Solution :
Python Code :
import numpy as np
x = np.random.uniform(1, 12, 5)
v = 4
n = x.flat[np.abs(x - v).argmin()]
print(n)
Sample Output:
4.2507132388
Explanation:
In the above exercise –
x = np.random.uniform(1, 12, 5): This line creates a 1D array x with 5 random numbers between 1 and 12 using the np.random.uniform() function. The input values 1 and 12 specify the lower and upper boundaries of the uniform distribution, and 5 is the size of the output array.
v = 4: This line assigns 4 to the variable v.
n = x.flat[np.abs(x - v).argmin()]: This line computes the closest element in the array x to the value v and assigns it to the variable n. The code performs the following operations:
- x - v: Calculates the difference between each element in the array x and the value v.
- np.abs(x - v): Returns the absolute value of the differences calculated in the previous step.
- np.abs(x - v).argmin(): Finds the index of the minimum value in the array of absolute differences.
- x.flat[np.abs(x - v).argmin()]: Uses the index found in the previous step to access the corresponding element in the flattened (1D) version of the array x and assigns it to the variable n.
print(n): Finally print() prints the value of the variable n.
Pictorial Presentation:
Python-Numpy Code Editor:
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Python: Tips of the Day
Returns the symmetric difference between two iterables, without filtering out duplicate values:
Example:
def tips_symmetric_difference(p, q): _p, _q = set(p), set(q) return [item for item in p if item not in _q] + [item for item in q if item not in _p] print(tips_symmetric_difference([2, 4, 6], [2, 4, 8]))
Output:
[6, 8]
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