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NumPy: Make all the elements of a given string to a numeric string of 5 digits with zeros on its left

NumPy String: Exercise-12 with Solution

Write a NumPy program to make all the elements of a given string to a numeric string of 5 digits with zeros on its left.

Sample Solution:-

Python Code:

import numpy as np
x = np.array(['2', '11', '234', '1234', '12345'], dtype=np.str)
print("\nOriginal Array:")
print(x)
r = np.char.zfill(x, 5)
print("\nNumeric string of 5 digits with zeros:")
print(r) 

Sample Input:

(['2', '11', '234', '1234', '12345'], dtype=np.str)

Sample Output:

Original Array:
['2' '11' '234' '1234' '12345']

Numeric string of 5 digits with zeros:
['00002' '00011' '00234' '01234' '12345']

Pictorial Presentation:

NumPy String: Make all the elements of a given string to a numeric string of 5 digits with zeros on its left

Python Code Editor:

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Python: Tips of the Day

Getting the last element of a list:

some_list[-1] is the shortest and most Pythonic.

In fact, you can do much more with this syntax. The some_list[-n] syntax gets the nth-to-last element. So some_list[-1] gets the last element, some_list[-2] gets the second to last, etc, all the way down to some_list[-len(some_list)], which gives you the first element.

You can also set list elements in this way. For instance:

>>> some_list = [1, 2, 3]
>>> some_list[-1] = 5 # Set the last element
>>> some_list[-2] = 3 # Set the second to last element
>>> some_list
[1, 3, 5]

Note that getting a list item by index will raise an IndexError if the expected item doesn't exist. This means that some_list[-1] will raise an exception if some_list is empty, because an empty list can't have a last element.

Ref: https://bit.ly/3d8TfFP