NumPy: Count a given word in each row of a array of string values
NumPy String: Exercise-21 with Solution
Write a NumPy program to count a given word in each row of a given array of string values.
import numpy as np str1 = np.array([['Python','NumPy','Exercises'], ['Python','Pandas','Exercises'], ['Python','Machine learning','Python']]) print("Original array of string values:") print(str1) print("\nCount 'Python' row wise in the above array of string values:") print(np.char.count(str1, 'Python'))
Original array of string values: [['Python' 'NumPy' 'Exercises'] ['Python' 'Pandas' 'Exercises'] ['Python' 'Machine learning' 'Python']] Count 'Python' row wise in the above array of string values: [[1 0 0] [1 0 0] [1 0 1]]
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Python: Tips of the Day
Getting the last element of a list:
some_list[-1] is the shortest and most Pythonic.
In fact, you can do much more with this syntax. The some_list[-n] syntax gets the nth-to-last element. So some_list[-1] gets the last element, some_list[-2] gets the second to last, etc, all the way down to some_list[-len(some_list)], which gives you the first element.
You can also set list elements in this way. For instance:
>>> some_list = [1, 2, 3] >>> some_list[-1] = 5 # Set the last element >>> some_list[-2] = 3 # Set the second to last element >>> some_list [1, 3, 5]
Note that getting a list item by index will raise an IndexError if the expected item doesn't exist. This means that some_list[-1] will raise an exception if some_list is empty, because an empty list can't have a last element.
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