﻿ Pandas: Split a given dataframe into groups with multiple aggregations - w3resource

# Pandas: Split a given dataframe into groups with multiple aggregations

## Pandas Grouping and Aggregating: Split-Apply-Combine Exercise-19 with Solution

Write a Pandas program to split a given dataframe into groups with multiple aggregations.
Split the following given dataframe by school code, class and get mean, min, and max value of height and age for each value of the school.

Test Data:

school class            name date_Of_Birth   age  height   weight  address
S1   s001     V  Alberto Franco     15/05/2002   12    173      35  street1
S2   s002     V    Gino Mcneill     17/05/2002   12    192      32  street2
S3   s003    VI     Ryan Parkes     16/02/1999   13    186      33  street3
S4   s001    VI    Eesha Hinton     25/09/1998   13    167      30  street1
S5   s002     V    Gino Mcneill     11/05/2002   14    151      31  street2
S6   s004    VI    David Parkes     15/09/1997   12    159      32  street4

Sample Solution:

Python Code :

import pandas as pd
pd.set_option('display.max_rows', None)
#pd.set_option('display.max_columns', None)
df = pd.DataFrame({
'school_code': ['s001','s002','s003','s001','s002','s001'],
'class': ['V', 'V', 'VI', 'VI', 'V', 'VI'],
'name': ['Alberto Franco','Gino Mcneill','Ryan Parkes', 'Eesha Hinton', 'Gino Mcneill', 'David Parkes'],
'date_Of_Birth ': ['15/05/2002','17/05/2002','16/02/1999','25/09/1998','11/05/2002','15/09/1997'],
'age': [12, 12, 13, 13, 14, 12],
'height': [173, 192, 186, 167, 151, 159],
'weight': [35, 32, 33, 30, 31, 32],
'address': ['street1', 'street2', 'street3', 'street1', 'street2', 'street4']},
index=['S1', 'S2', 'S3', 'S4', 'S5', 'S6'])
print("Original DataFrame:")
print(df)
print("\nGroup by with multiple aggregations:")
result = df.groupby(['school_code','class']).agg({'height': ['max', 'mean'],
'weight': ['sum','min','count']})
print(result)

Sample Output:

Original DataFrame:
school_code class            name   ...    height  weight  address
S1        s001     V  Alberto Franco   ...       173      35  street1
S2        s002     V    Gino Mcneill   ...       192      32  street2
S3        s003    VI     Ryan Parkes   ...       186      33  street3
S4        s001    VI    Eesha Hinton   ...       167      30  street1
S5        s002     V    Gino Mcneill   ...       151      31  street2
S6        s001    VI    David Parkes   ...       159      32  street4

[6 rows x 8 columns]

Group by with multiple aggregations:
height        weight
max   mean    sum min count
school_code class
s001        V        173  173.0     35  35     1
VI       167  163.0     62  30     2
s002        V        192  171.5     63  31     2
s003        VI       186  186.0     33  33     1

Python Code Editor:

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## Python: Tips of the Day

Understanding slice notation:

It's pretty simple really:

a[start:stop]  # items start through stop-1
a[start:]      # items start through the rest of the array
a[:stop]       # items from the beginning through stop-1
a[:]           # a copy of the whole array

There is also the step value, which can be used with any of the above:

a[start:stop:step] # start through not past stop, by step

The key point to remember is that the :stop value represents the first value that is not in the selected slice. So, the difference between stop and start is the number of elements selected (if step is 1, the default).

The other feature is that start or stop may be a negative number, which means it counts from the end of the array instead of the beginning. So:

a[-1]    # last item in the array
a[-2:]   # last two items in the array
a[:-2]   # everything except the last two items

Similarly, step may be a negative number:

a[::-1]    # all items in the array, reversed
a[1::-1]   # the first two items, reversed
a[:-3:-1]  # the last two items, reversed
a[-3::-1]  # everything except the last two items, reversed

Python is kind to the programmer if there are fewer items than you ask for. For example, if you ask for a[:-2] and a only contains one element, you get an empty list instead of an error. Sometimes you would prefer the error, so you have to be aware that this may happen.

Relation to slice() object

The slicing operator [] is actually being used in the above code with a slice() object using the : notation (which is only valid within []), i.e.:

a[start:stop:step]

is equivalent to:

a[slice(start, stop, step)]

Slice objects also behave slightly differently depending on the number of arguments, similarly to range(), i.e. both slice(stop) and slice(start, stop[, step]) are supported. To skip specifying a given argument, one might use None, so that e.g. a[start:] is equivalent to a[slice(start, None)] or a[::-1] is equivalent to a[slice(None, None, -1)].

While the : -based notation is very helpful for simple slicing, the explicit use of slice() objects simplifies the programmatic generation of slicing.

Ref: https://bit.ly/2MHaTp7