Pandas: Relative frequency within each group
Pandas Grouping and Aggregating: Split-Apply-Combine Exercise-24 with Solution
Write a Pandas program to split the following datasets into groups on customer_id to summarize purch_amt and calculate percentage of purch_amt in each group.
Test Data:
ord_no purch_amt ord_date customer_id salesman_id 0 70001 150.50 05-10-2012 3001 5002 1 70009 270.65 09-10-2012 3001 5005 2 70002 65.26 05-10-2012 3005 5001 3 70004 110.50 08-17-2012 3001 5003 4 70007 948.50 10-09-2012 3005 5002 5 70005 2400.60 07-27-2012 3001 5001 6 70008 5760.00 10-09-2012 3005 5001 7 70010 1983.43 10-10-2012 3001 5006 8 70003 2480.40 10-10-2012 3005 5003 9 70012 250.45 06-17-2012 3001 5002 10 70011 75.29 07-08-2012 3005 5007 11 70013 3045.60 04-25-2012 3005 5001
Sample Solution:
Python Code :
import pandas as pd
pd.set_option('display.max_rows', None)
#pd.set_option('display.max_columns', None)
df = pd.DataFrame({
'ord_no':[70001,70009,70002,70004,70007,70005,70008,70010,70003,70012,70011,70013],
'purch_amt':[150.5,270.65,65.26,110.5,948.5,2400.6,5760,1983.43,2480.4,250.45, 75.29,3045.6],
'ord_date': ['05-10-2012','09-10-2012','05-10-2012','08-17-2012','10-09-2012','07-27-2012','10-09-2012','10-10-2012','10-10-2012','06-17-2012','07-08-2012','04-25-2012'],
'customer_id':[3001,3001,3005,3001,3005,3001,3005,3001,3005,3001,3005,3005],
'salesman_id': [5002,5005,5001,5003,5002,5001,5001,5006,5003,5002,5007,5001]})
print("Original Orders DataFrame:")
print(df)
gr_data = df.groupby(['customer_id','salesman_id']).agg({'purch_amt': 'sum'})
gr_data["% (Purch Amt.)"] = gr_data.apply(lambda x: 100*x / x.sum())
print("\nPercentage of purch_amt in each group of customer_id:")
print(gr_data)
Sample Output:
Original Orders DataFrame: ord_no purch_amt ord_date customer_id salesman_id 0 70001 150.50 05-10-2012 3001 5002 1 70009 270.65 09-10-2012 3001 5005 2 70002 65.26 05-10-2012 3005 5001 3 70004 110.50 08-17-2012 3001 5003 4 70007 948.50 10-09-2012 3005 5002 5 70005 2400.60 07-27-2012 3001 5001 6 70008 5760.00 10-09-2012 3005 5001 7 70010 1983.43 10-10-2012 3001 5006 8 70003 2480.40 10-10-2012 3005 5003 9 70012 250.45 06-17-2012 3001 5002 10 70011 75.29 07-08-2012 3005 5007 11 70013 3045.60 04-25-2012 3005 5001 Percentage of purch_amt in each group of customer_id: purch_amt % (Purch Amt.) customer_id salesman_id 3001 5001 2400.60 13.685510 5002 400.95 2.285764 5003 110.50 0.629946 5005 270.65 1.542941 5006 1983.43 11.307278 3005 5001 8870.86 50.571626 5002 948.50 5.407276 5003 2480.40 14.140440 5007 75.29 0.429219
Python Code Editor:
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Next: Write a Pandas program to split a dataset, group by one column and get mean, min, and max values by group, also change the column name of the aggregated metric. Using the following dataset find the mean, min, and max values of purchase amount (purch_amt) group by customer id (customer_id).What is the difficulty level of this exercise?
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