﻿ Pandas Practice Set-1: Find the diamonds that are either Premium or Ideal - w3resource # Pandas Practice Set-1: Find the diamonds that are either Premium or Ideal

## Pandas Practice Set-1: Exercise-18 with Solution

Write a Pandas program to find the diamonds that are either Premium or Ideal.

Sample Solution:

Python Code:

``````import pandas as pd
print("Original Dataframe:")
print("\nDiamonds that are either Premium or Ideal:")
result = diamonds[(diamonds.cut == 'Premium') | (diamonds.cut == 'Ideal')]
``````

Sample Output:

```Original Dataframe:
carat      cut color clarity  depth  table  price     x     y     z
0   0.23    Ideal     E     SI2   61.5   55.0    326  3.95  3.98  2.43
1   0.21  Premium     E     SI1   59.8   61.0    326  3.89  3.84  2.31
2   0.23     Good     E     VS1   56.9   65.0    327  4.05  4.07  2.31
3   0.29  Premium     I     VS2   62.4   58.0    334  4.20  4.23  2.63
4   0.31     Good     J     SI2   63.3   58.0    335  4.34  4.35  2.75

Diamonds that are either Premium or Ideal:
carat      cut color clarity  depth  table  price     x     y     z
0    0.23    Ideal     E     SI2   61.5   55.0    326  3.95  3.98  2.43
1    0.21  Premium     E     SI1   59.8   61.0    326  3.89  3.84  2.31
3    0.29  Premium     I     VS2   62.4   58.0    334  4.20  4.23  2.63
11   0.23    Ideal     J     VS1   62.8   56.0    340  3.93  3.90  2.46
12   0.22  Premium     F     SI1   60.4   61.0    342  3.88  3.84  2.33
```

Python Code Editor:

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## Python: Tips of the Day

Returns the symmetric difference between two lists, after applying the provided function to each list element of both

Example:

```def tips_symmetric_difference_by(p, q, fn):
_p, _q = set(map(fn, p)), set(map(fn, q))
return [item for item in p if fn(item) not in _q] + [item for item in q if fn(item) not in _p]
from math import floor
print(tips_symmetric_difference_by([4.2, 2.4], [4.6, 6.8],floor))
```

Output:

```[2.4, 6.8]
```