﻿ Pandas: Delete DataFrame row(s) based on given column value - w3resource

# Pandas: Delete DataFrame row(s) based on given column value

## Pandas: DataFrame Exercise-29 with Solution

Write a Pandas program to delete DataFrame row(s) based on given column value.

Sample data:
Original DataFrame
col1 col2 col3
0 1 4 7
1 4 5 8
2 3 6 9
3 4 7 0
4 5 8 1
New DataFrame
col1 col2 col3
0 1 4 7
2 3 6 9
3 4 7 0
4 5 8 1

Sample Solution :

Python Code :

``````import pandas as pd
import numpy as np
d = {'col1': [1, 4, 3, 4, 5], 'col2': [4, 5, 6, 7, 8], 'col3': [7, 8, 9, 0, 1]}
df = pd.DataFrame(data=d)
print("Original DataFrame")
print(df)
df = df[df.col2 != 5]
print("New DataFrame")
print(df)
``````

Sample Output:

```    Original DataFrame
col1  col2  col3
0     1     4     7
1     4     5     8
2     3     6     9
3     4     7     0
4     5     8     1
New DataFrame
col1  col2  col3
0     1     4     7
2     3     6     9
3     4     7     0
4     5     8     1
```

Python-Pandas Code Editor:

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## Python: Tips of the Day

Inserting if statements using conditional list comprehensions:

```x = [1, 2, 3, 4, 5, 6]
result = []
for idx in range(len(x)):
if x[idx] % 2 == 0:
result.append(x[idx] * 2)
else:
result.append(x[idx])
result
```

Output:

```[1, 4, 3, 8, 5, 12]
```
`[(element * 2 if element % 2 == 0 else element) for element in x]`

Output:

```[1, 4, 3, 8, 5, 12]
```
`[element * 2 for element in x if element % 2 == 0]`

Output:

```[4, 8, 12]
```