Python: Find four positive even integers whose sum is n
Python Programming Puzzles: Exercise-100 with Solution
Write a Python program to find four positive even integers whose sum is a given integer.
Input: n = 100 Output: [94, 2, 2, 2] Input: n = 1000 Output: [994, 2, 2, 2] Input: n = 10000 Output: [9994, 2, 2, 2] Input: n = 1234567890 Output: [1234567884, 2, 2, 2]
Sample Solution:
Python Code:
#License: https://bit.ly/3oLErEI
def test(n):
for a in range(n, 0, -1):
if not a % 2 == 0:
continue
for b in range(n - a, 0, -1):
if not b % 2 == 0:
continue
for c in range(n - b - a, 0, -1):
if not c % 2 == 0:
continue
for d in range(n - b - c - a, 0, -1):
if not d % 2 == 0:
continue
if a + b + c + d == n:
return [a, b, c, d]
n = 100
print("Four positive even integers whose sum is",n)
print(test(n))
n = 1000
print("\nFour positive even integers whose sum is",n)
print(test(n))
n = 10000
print("\nFour positive even integers whose sum is",n)
print(test(n))
n = 1234567890
print("\nFour positive even integers whose sum is",n)
print(test(n))
Sample Output:
Four positive even integers whose sum is 100 [94, 2, 2, 2] Four positive even integers whose sum is 1000 [994, 2, 2, 2] Four positive even integers whose sum is 10000 [9994, 2, 2, 2] Four positive even integers whose sum is 1234567890 [1234567884, 2, 2, 2]
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Python: Tips of the Day
Clamps num within the inclusive range specified by the boundary values x and y:
Example:
def tips_clamp_num(num,x,y): return max(min(num, max(x, y)), min(x, y)) print(tips_clamp_num(2, 4, 6)) print(tips_clamp_num(1, -1, -6))
Output:
4 -1
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