Python: Product of the odd digits in n, or 0 if there aren't any

Python Programming Puzzles: Exercise-35 with Solution

Write a Python program to compute the product of the odd digits in a given number, or 0 if there aren't any.

Input:  
123456789
Output:
945

Input:  
2468
Output:
0

Input:  
13579
Output:
945

Pictorial Presentation:

Sample Solution:

Python Code:

#License: https://bit.ly/3oLErEI

def test(n):
    if any(int(c) % 2 for c in str(n)):
        prod = 1
        for c in str(n):
            if int(c) % 2 == 1:
                prod *= int(c)
        return prod
    return 0

n = 123456789
print("Original Number:",n)
print("Product of the odd digits in the said number, or 0 if there aren't any")
print(test(n))
n = 2468
print("\nOriginal Number:",n)
print("Product of the odd digits in the said number, or 0 if there aren't any")
print(test(n))
n = 13579
print("\nOriginal Number:",n)
print("Product of the odd digits in the said number, or 0 if there aren't any")
print(test(n))

Sample Output:

Original Number: 123456789
Product of the odd digits in the said number, or 0 if there aren't any
945

Original Number: 2468
Product of the odd digits in the said number, or 0 if there aren't any
0

Original Number: 13579
Product of the odd digits in the said number, or 0 if there aren't any
945

Flowchart:

Python Code Editor :

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