Python: Product of the odd digits in n, or 0 if there aren't any
Python Programming Puzzles: Exercise-35 with Solution
Write a Python program to compute the product of the odd digits in a given number, or 0 if there aren't any.
Input: 123456789 Output: 945 Input: 2468 Output: 0 Input: 13579 Output: 945
Pictorial Presentation:



Sample Solution:
Python Code:
#License: https://bit.ly/3oLErEI
def test(n):
if any(int(c) % 2 for c in str(n)):
prod = 1
for c in str(n):
if int(c) % 2 == 1:
prod *= int(c)
return prod
return 0
n = 123456789
print("Original Number:",n)
print("Product of the odd digits in the said number, or 0 if there aren't any")
print(test(n))
n = 2468
print("\nOriginal Number:",n)
print("Product of the odd digits in the said number, or 0 if there aren't any")
print(test(n))
n = 13579
print("\nOriginal Number:",n)
print("Product of the odd digits in the said number, or 0 if there aren't any")
print(test(n))
Sample Output:
Original Number: 123456789 Product of the odd digits in the said number, or 0 if there aren't any 945 Original Number: 2468 Product of the odd digits in the said number, or 0 if there aren't any 0 Original Number: 13579 Product of the odd digits in the said number, or 0 if there aren't any 945
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Python: Tips of the Day
Clamps num within the inclusive range specified by the boundary values x and y:
Example:
def tips_clamp_num(num,x,y): return max(min(num, max(x, y)), min(x, y)) print(tips_clamp_num(2, 4, 6)) print(tips_clamp_num(1, -1, -6))
Output:
4 -1
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