# Python: Product of the odd digits in n, or 0 if there aren't any

## Python Programming Puzzles: Exercise-35 with Solution

Write a Python program to compute the product of the odd digits in a given number, or 0 if there aren't any.

Input: 123456789 Output: 945 Input: 2468 Output: 0 Input: 13579 Output: 945

**Pictorial Presentation:**

**Sample Solution:**

**Python Code:**

```
#License: https://bit.ly/3oLErEI
def test(n):
if any(int(c) % 2 for c in str(n)):
prod = 1
for c in str(n):
if int(c) % 2 == 1:
prod *= int(c)
return prod
return 0
n = 123456789
print("Original Number:",n)
print("Product of the odd digits in the said number, or 0 if there aren't any")
print(test(n))
n = 2468
print("\nOriginal Number:",n)
print("Product of the odd digits in the said number, or 0 if there aren't any")
print(test(n))
n = 13579
print("\nOriginal Number:",n)
print("Product of the odd digits in the said number, or 0 if there aren't any")
print(test(n))
```

Sample Output:

Original Number: 123456789 Product of the odd digits in the said number, or 0 if there aren't any 945 Original Number: 2468 Product of the odd digits in the said number, or 0 if there aren't any 0 Original Number: 13579 Product of the odd digits in the said number, or 0 if there aren't any 945

**Flowchart:**

**Python Code Editor :**

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