# Python: Find the number of stones in each pile

## Python Programming Puzzles: Exercise-4 with Solution

We are making n stone piles! The first pile has n stones. If n is even, then all piles have an even number of stones. If n is odd, all piles have an odd number of stones. Each pile must more stones than the previous pile but as few as possible. Write a Python program to find the number of stones in each pile.

Input: 2 Output: [2, 4] Input: 10 Output: [10, 12, 14, 16, 18, 20, 22, 24, 26, 28] Input: 3 Output: [3, 5, 7] Input: 17 Output: [17, 19, 21, 23, 25, 27, 29, 31, 33, 35, 37, 39, 41, 43, 45, 47, 49]

**Pictorial Presentation:**

**Sample Solution:**

**Python Code:**

```
#License: https://bit.ly/3oLErEI
def test(n):
return [n + 2 * i for i in range(n)]
n = 2
print("Number of piles:",n)
print("Number of stones in each pile:")
print(test(n))
n = 10
print("\nNumber of piles:",n)
print("Number of stones in each pile:")
print(test(n))
n = 3
print("\nNumber of piles:",n)
print("Number of stones in each pile:")
print(test(n))
n = 17
print("\nNumber of piles:",n)
print("Number of stones in each pile:")
print(test(n))
```

Sample Output:

Number of piles: 2 Number of stones in each pile: [2, 4] Number of piles: 10 Number of stones in each pile: [10, 12, 14, 16, 18, 20, 22, 24, 26, 28] Number of piles: 3 Number of stones in each pile: [3, 5, 7] Number of piles: 17 Number of stones in each pile: [17, 19, 21, 23, 25, 27, 29, 31, 33, 35, 37, 39

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