Python: Find the dictionary key whose case is different than all other keys
Python Programming Puzzles: Exercise-62 with Solution
Write a Python program to find the dictionary key whose case is different than all other keys.
Input: {'red': '', 'GREEN': '', 'blue': 'orange'} Output: GREEN Input: {'RED': '', 'GREEN': '', 'orange': '#125GD'} Output: orange
Pictorial Presentation:

Sample Solution:
Python Code:
#License: https://bit.ly/3oLErEI
def test(dict_data):
for different in dict_data:
if all(k.islower() != different.islower() for k in dict_data if k != different):
return different
dict_data = {"red": "", "GREEN": "", "blue": "orange"}
print("Original dictionary key-values:")
print(dict_data)
print("Find the dictionary key whose case is different than all other keys:")
print(test(dict_data))
dict_data = {"RED": "", "GREEN": "", "orange": "#125GD"}
print("\nOriginal dictionary key-values:")
print(dict_data)
print("Find the dictionary key whose case is different than all other keys:")
print(test(dict_data))
Sample Output:
Original dictionary key-values: {'red': '', 'GREEN': '', 'blue': 'orange'} Find the dictionary key whose case is different than all other keys: GREEN Original dictionary key-values: {'RED': '', 'GREEN': '', 'orange': '#125GD'} Find the dictionary key whose case is different than all other keys: orange
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Python: Tips of the Day
Clamps num within the inclusive range specified by the boundary values x and y:
Example:
def tips_clamp_num(num,x,y): return max(min(num, max(x, y)), min(x, y)) print(tips_clamp_num(2, 4, 6)) print(tips_clamp_num(1, -1, -6))
Output:
4 -1
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