Python: Find the dictionary key whose case is different than all other keys

Python Programming Puzzles: Exercise-62 with Solution

Write a Python program to find the dictionary key whose case is different from all other keys.

Input:
{'red': '', 'GREEN': '', 'blue': 'orange'}
Output:
GREEN

Input:
{'RED': '', 'GREEN': '', 'orange': '#125GD'}
Output:
orange

Pictorial Presentation:

Sample Solution:

Python Code:

#License: https://bit.ly/3oLErEI

def test(dict_data):
    for different in dict_data:
        if all(k.islower() != different.islower() for k in dict_data if k != different):
            return different
 
dict_data = {"red": "", "GREEN": "", "blue": "orange"}
print("Original dictionary key-values:")
print(dict_data)
print("Find the dictionary key whose case is different than all other keys:")
print(test(dict_data)) 
dict_data = {"RED": "", "GREEN": "", "orange": "#125GD"}
print("\nOriginal dictionary key-values:")
print(dict_data)
print("Find the dictionary key whose case is different than all other keys:")
print(test(dict_data))

Sample Output:

Original dictionary key-values:
{'red': '', 'GREEN': '', 'blue': 'orange'}
Find the dictionary key whose case is different than all other keys:
GREEN

Original dictionary key-values:
{'RED': '', 'GREEN': '', 'orange': '#125GD'}
Find the dictionary key whose case is different than all other keys:
orange

Flowchart:

Python Code Editor :

Have another way to solve this solution? Contribute your code (and comments) through Disqus.

Previous: Find the number which when appended to the list makes the total 0.
Next: Find the sum of the even elements that are at odd indices in a given list.