Python: Find the indices of the closest pair from given a list of numbers
Python Programming Puzzles: Exercise-66 with Solution
Write a Python program to find the indices of the closest pair from a list of numbers.
Input: [1, 7, 9, 2, 10] Output: [0, 3] Input: [1.1, 4.25, 0.79, 1.0, 4.23] Output: [4, 1] Input: [0.21, 11.3, 2.01, 8.0, 10.0, 3.0, 15.2] Output: [2, 5]
Pictorial Presentation:

Sample Solution:
Python Code:
#License: https://bit.ly/3oLErEI
def test(nums):
closest_inds = None
closest_dist = None
for ind, num in enumerate(nums):
for other_ind, num2 in enumerate(nums):
if num != num2 and ((closest_dist is None) or abs(num - num2) < closest_dist):
closest_dist = abs(num - num2)
closest_inds = [ind, other_ind]
if num <= num2:
closest_inds = [ind, other_ind]
else:
closest_inds = [other_ind, ind]
return closest_inds
nums = [1, 7, 9, 2, 10]
print("List of numbers:",nums)
print("Indices of the closest pair from the said list of numbers:")
print(test(nums))
nums = [1.1, 4.25, 0.79, 1.0, 4.23]
print("\nList of numbers:",nums)
print("Indices of the closest pair from the said list of numbers:")
print(test(nums))
nums = [0.21, 11.3, 2.01, 8.0, 10.0, 3.0, 15.2]
print("\nList of numbers:",nums)
print("Indices of the closest pair from the said list of numbers:")
print(test(nums))
Sample Output:
List of numbers: [1, 7, 9, 2, 10] Indices of the closest pair from the said list of numbers: [0, 3] List of numbers: [1.1, 4.25, 0.79, 1.0, 4.23] Indices of the closest pair from the said list of numbers: [4, 1] List of numbers: [0.21, 11.3, 2.01, 8.0, 10.0, 3.0, 15.2] Indices of the closest pair from the said list of numbers: [2, 5]
Flowchart:

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Python: Tips of the Day
Returns the symmetric difference between two iterables, without filtering out duplicate values:
Example:
def tips_symmetric_difference(p, q): _p, _q = set(p), set(q) return [item for item in p if item not in _q] + [item for item in q if item not in _p] print(tips_symmetric_difference([2, 4, 6], [2, 4, 8]))
Output:
[6, 8]
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