Python: Find all 5's in integers less than n that are divisible by 9 or 15
Python Programming Puzzles: Exercise-68 with Solution
Write a Python program to find all 5's in integers less than n that are divisible by 9 or 15.
Input: Value of n = 50 Output: [[15, 1], [45, 1]] Input: Value of n = 65 Output: [[15, 1], [45, 1], [54, 0]] Input: Value of n = 75 Output: [[15, 1], [45, 1], [54, 0]] Input: Value of n = 85 Output: [[15, 1], [45, 1], [54, 0], [75, 1]] Input: Value of n = 150 Output: [[15, 1], [45, 1], [54, 0], [75, 1], [105, 2], [135, 2]]
Pictorial Presentation:

Sample Solution-1:
Python Code:
def test(n):
return [[i,j] for i in range(n) for j in range(len(str(i))) if str(i)[j] == '5' and (i%15==0 or i%9==0)]
n = 50
print("Value of n = ",n)
print("5's in integers less than",n,"that are divisible by 9 or 15:")
print(test(n))
n = 65
print("\nValue of n = ",n)
print("5's in integers less than",n,"that are divisible by 9 or 15:")
print(test(n))
n = 75
print("\nValue of n = ",n)
print("5's in integers less than",n,"that are divisible by 9 or 15:")
print(test(n))
n = 85
print("\nValue of n = ",n)
print("5's in integers less than",n,"that are divisible by 9 or 15:")
print(test(n))
n = 150
print("\nValue of n = ",n)
print("5's in integers less than",n,"that are divisible by 9 or 15:")
print(test(n))
Sample Output:
Value of n = 50 5's in integers less than 50 that are divisible by 9 or 15: [[15, 1], [45, 1]] Value of n = 65 5's in integers less than 65 that are divisible by 9 or 15: [[15, 1], [45, 1], [54, 0]] Value of n = 75 5's in integers less than 75 that are divisible by 9 or 15: [[15, 1], [45, 1], [54, 0]] Value of n = 85 5's in integers less than 85 that are divisible by 9 or 15: [[15, 1], [45, 1], [54, 0], [75, 1]] Value of n = 150 5's in integers less than 150 that are divisible by 9 or 15: [[15, 1], [45, 1], [54, 0], [75, 1], [105, 2], [135, 2]]
Flowchart:

Sample Solution-2:
Python Code:
def test(n):
return [[i, j] for i in range(n) if (i % 9 == 0 or i % 15 == 0) for j, c in enumerate(str(i)) if c == '5']
n = 50
print("Value of n = ",n)
print("5's in integers less than",n,"that are divisible by 9 or 15:")
print(test(n))
n = 65
print("\nValue of n = ",n)
print("5's in integers less than",n,"that are divisible by 9 or 15:")
print(test(n))
n = 75
print("\nValue of n = ",n)
print("5's in integers less than",n,"that are divisible by 9 or 15:")
print(test(n))
n = 85
print("\nValue of n = ",n)
print("5's in integers less than",n,"that are divisible by 9 or 15:")
print(test(n))
n = 150
print("\nValue of n = ",n)
print("5's in integers less than",n,"that are divisible by 9 or 15:")
print(test(n))
Sample Output:
Value of n = 50 5's in integers less than 50 that are divisible by 9 or 15: [[15, 1], [45, 1]] Value of n = 65 5's in integers less than 65 that are divisible by 9 or 15: [[15, 1], [45, 1], [54, 0]] Value of n = 75 5's in integers less than 75 that are divisible by 9 or 15: [[15, 1], [45, 1], [54, 0]] Value of n = 85 5's in integers less than 85 that are divisible by 9 or 15: [[15, 1], [45, 1], [54, 0], [75, 1]] Value of n = 150 5's in integers less than 150 that are divisible by 9 or 15: [[15, 1], [45, 1], [54, 0], [75, 1], [105, 2], [135, 2]]
Flowchart:

Python Code Editor :
Have another way to solve this solution? Contribute your code (and comments) through Disqus.
Previous: Find a string which, when each character is shifted (ASCII incremented) by shift.
Next: Create a new string by taking s, and word by word rearranging its characters in ASCII order.
What is the difficulty level of this exercise?
Test your Programming skills with w3resource's quiz.
- Weekly Trends
- Python Interview Questions and Answers: Comprehensive Guide
- Scala Exercises, Practice, Solution
- Kotlin Exercises practice with solution
- MongoDB Exercises, Practice, Solution
- SQL Exercises, Practice, Solution - JOINS
- Java Basic Programming Exercises
- SQL Subqueries
- Adventureworks Database Exercises
- C# Sharp Basic Exercises
- SQL COUNT() with distinct
- JavaScript String Exercises
- JavaScript HTML Form Validation
- Java Collection Exercises
- SQL COUNT() function
- SQL Inner Join