w3resource

Python: Inject a number in between each pair of adjacent numbers in a list of numbers

Python Programming Puzzles: Exercise-71 with Solution

Given a list of numbers and a number to inject, write a Python program to create a list containing that number in between each pair of adjacent numbers.

Input: [12, -7, 3, -89, 14, 88, -78, -1, 2, 7]
Separator: 6
Output:
[12, 6, -7, 6, 3, 6, -89, 6, 14, 6, 88, 6, -78, 6, -1, 6, 2, 6, 7]

Input: [1, 2, 3, 4, 5, 6]
Separator: 9
Output:
[1, 9, 2, 9, 3, 9, 4, 9, 5, 9, 6]

Visual Presentation:

Python: Inject a number in between each pair of adjacent numbers in a list of numbers.

Sample Solution-1:

Python Code:

# License: https://bit.ly/3oLErEI

# Define a function named 'test' that takes a list of numbers and a separator as input
def test(nums, sep):
    # Initialize a list 'ans' with double the length of 'nums' minus one, filled with separators
    ans = [sep] * (2 * len(nums) - 1)
    
    # Replace every second element of 'ans' with the corresponding elements from 'nums'
    ans[::2] = nums
    
    return ans  # Return the modified list

# Example 1
nums1 = [12, -7, 3, -89, 14, 88, -78, -1, 2, 7]
separator1 = 6
print("List of numbers:", nums1)
print("Separator:", separator1)
print("Inject the separator in between each pair of adjacent numbers of the said list:")
print(test(nums1, separator1))

# Example 2
nums2 = [1, 2, 3, 4, 5, 6]
separator2 = 9
print("\nList of numbers:", nums2)
print("Separator:", separator2)
print("Inject the separator in between each pair of adjacent numbers of the said list:")
print(test(nums2, separator2))

Sample Output:

List of numbers: [12, -7, 3, -89, 14, 88, -78, -1, 2, 7]
Separator: 6
Inject the separator in between each pair of adjacent numbers of the said list:
[12, 6, -7, 6, 3, 6, -89, 6, 14, 6, 88, 6, -78, 6, -1, 6, 2, 6, 7]

List of numbers: [1, 2, 3, 4, 5, 6]
Separator: 9
Inject the separator in between each pair of adjacent numbers of the said list:
[1, 9, 2, 9, 3, 9, 4, 9, 5, 9, 6]

Flowchart:

Flowchart: Python - Inject a number in between each pair of adjacent numbers in a list of numbers.

Sample Solution-2:

Python Code:

# License: https://bit.ly/3oLErEI

# Define a function named 'test' that takes a list of numbers and a separator as input
def test(nums, sep):
    result = []  # Initialize an empty list to store the result
    
    # Iterate through the indices of 'nums'
    for i in range(len(nums)):
        # Check if the current index is the last one
        if i == len(nums) - 1:
            result.append(nums[i])  # If it is the last index, append the number without the separator
        else:
            result.append(nums[i])  # Append the current number to the result
            result.append(sep)      # Append the separator after the current number
    
    return result  # Return the modified list

# Example 1
nums1 = [12, -7, 3, -89, 14, 88, -78, -1, 2, 7]
separator1 = 6
print("List of numbers:", nums1)
print("Separator:", separator1)
print("Inject the separator in between each pair of adjacent numbers of the said list:")
print(test(nums1, separator1))

# Example 2
nums2 = [1, 2, 3, 4, 5, 6]
separator2 = 9
print("\nList of numbers:", nums2)
print("Separator:", separator2)
print("Inject the separator in between each pair of adjacent numbers of the said list:")
print(test(nums2, separator2))

Sample Output:

List of numbers: [12, -7, 3, -89, 14, 88, -78, -1, 2, 7]
Separator: 6
Inject the separator in between each pair of adjacent numbers of the said list:
[12, 6, -7, 6, 3, 6, -89, 6, 14, 6, 88, 6, -78, 6, -1, 6, 2, 6, 7]

List of numbers: [1, 2, 3, 4, 5, 6]
Separator: 9
Inject the separator in between each pair of adjacent numbers of the said list:
[1, 9, 2, 9, 3, 9, 4, 9, 5, 9, 6]

Python Code Editor :

Have another way to solve this solution? Contribute your code (and comments) through Disqus.

Previous: Find the first negative balance.
Next: Find the indices of three numbers that sum to 0 in a list.

What is the difficulty level of this exercise?

Test your Programming skills with w3resource's quiz.



Follow us on Facebook and Twitter for latest update.