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Python: Reorder numbers in increasing/decreasing order based on whether the first plus last element is even/odd

Python Programming Puzzles: Exercise-75 with Solution

Write a Python program to reorder numbers from a given array in increasing/decreasing order based on whether the first plus last element is odd/even.

Input: 
[3, 7, 4]
Output:
[3, 4, 7]

Input:  
[2, 7, 4]
Output:
[7, 4, 2]

Input: 
[1, 5, 6, 7, 4, 2, 8] 
Output:
[1, 2, 4, 5, 6, 7, 8]

Input:  
[1, 5, 6, 7, 4, 2, 9]
Output:
[9, 7, 6, 5, 4, 2, 1]

Pictorial Presentation:

Python: Reorder numbers in increasing/decreasing order based on whether the first plus last element is even/odd.
Python: Reorder numbers in increasing/decreasing order based on whether the first plus last element is even/odd.

Sample Solution:

Python Code:

#License: https://bit.ly/3oLErEI

def test(nums):
     return sorted(nums, reverse=(False if (nums[0] + nums[-1]) % 2 else True)) 
print("Reorder numbers of a give array in increasing/decreasing order based on whether the first plus last element is odd/even.:") 
nums = [3, 7, 4]
print("\nList of numbers:",nums)
print("Result:")
print(test(nums))
nums = [2, 7, 4]
print("\nList of numbers:",nums)
print("Result:")
print(test(nums))
nums = [1, 5, 6, 7, 4, 2, 8]
print("\nList of numbers:",nums)
print("Result:")
print(test(nums))
nums = [1, 5, 6, 7, 4, 2, 9]
print("\nList of numbers:",nums)
print("Result:")
print(test(nums))

Sample Output:

Reorder numbers of a give array in increasing/decreasing order based on whether the first plus last element is odd/even.:

List of numbers: [3, 7, 4]
Result:
[3, 4, 7]

List of numbers: [2, 7, 4]
Result:
[7, 4, 2]

List of numbers: [1, 5, 6, 7, 4, 2, 8]
Result:
[1, 2, 4, 5, 6, 7, 8]

List of numbers: [1, 5, 6, 7, 4, 2, 9]
Result:
[9, 7, 6, 5, 4, 2, 1]

Flowchart:

Flowchart: Python - Reorder numbers in increasing/decreasing order based on whether the first plus last element is even/odd.

Python Code Editor :

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