Python: Convert GPAs to letter grades
Python Programming Puzzles: Exercise-77 with Solution
Write a Python program to convert GPAs to letter grades according to the following table:
GPAs | Grades |
---|---|
4.0: | A+ |
3.7: | A |
3.4: | A- |
3.0: | B+ |
2.7: | B |
2.4: | B- |
2.0: | C+ |
1.7: | C |
1.4: | C- |
below: | F |
Input: [4.0, 3.5, 3.8] Output: ['A+', 'A-', 'A'] Input: [5.0, 4.7, 3.4, 3.0, 2.7, 2.4, 2.0, 1.7, 1.4, 0.0] Output: ['A+', 'A+', 'A-', 'B+', 'B', 'B-', 'C+', 'C', 'C-', 'F']
Sample Solution:
Python Code:
#License: https://bit.ly/3oLErEI
def test(nums):
return ["A+" if grade >= 4.0
else ("A" if grade >= 3.7
else ("A-" if grade >= 3.4
else ("B+" if grade >= 3.0
else ("B" if grade >= 2.7
else ("B-" if grade >= 2.4
else ("C+" if grade >= 2.0
else ("C" if grade >= 1.7
else ("C-" if grade >= 1.4
else "F"))))))))
for grade in nums]
nums = [4.0, 3.5, 3.8]
print("List of numbers:",nums)
print("Convert GPAs to letter grades:")
print(test(nums))
nums = [5.0, 4.7, 3.4, 3.0, 2.7, 2.4, 2.0, 1.7, 1.4, 0.0]
print("\nList of numbers:",nums)
print("Convert GPAs to letter grades:")
print(test(nums))
Sample Output:
List of numbers: [4.0, 3.5, 3.8] Convert GPAs to letter grades: ['A+', 'A-', 'A'] List of numbers: [5.0, 4.7, 3.4, 3.0, 2.7, 2.4, 2.0, 1.7, 1.4, 0.0] Convert GPAs to letter grades: ['A+', 'A+', 'A-', 'B+', 'B', 'B-', 'C+', 'C', 'C-', 'F']
Flowchart:

Visualize Python code execution:
The following tool visualize what the computer is doing step-by-step as it executes the said program:
Python Code Editor :
Have another way to solve this solution? Contribute your code (and comments) through Disqus.
Previous: Find the index of the largest prime in the list and the sum of its digits.
Next: Find the two closest distinct numbers in a given a list of numbers.
What is the difficulty level of this exercise?
Test your Programming skills with w3resource's quiz.
Python: Tips of the Day
Clamps num within the inclusive range specified by the boundary values x and y:
Example:
def tips_clamp_num(num,x,y): return max(min(num, max(x, y)), min(x, y)) print(tips_clamp_num(2, 4, 6)) print(tips_clamp_num(1, -1, -6))
Output:
4 -1
- New Content published on w3resource:
- HTML-CSS Practical: Exercises, Practice, Solution
- Java Regular Expression: Exercises, Practice, Solution
- Scala Programming Exercises, Practice, Solution
- Python Itertools exercises
- Python Numpy exercises
- Python GeoPy Package exercises
- Python Pandas exercises
- Python nltk exercises
- Python BeautifulSoup exercises
- Form Template
- Composer - PHP Package Manager
- PHPUnit - PHP Testing
- Laravel - PHP Framework
- Angular - JavaScript Framework
- Vue - JavaScript Framework
- Jest - JavaScript Testing Framework