# Python: Calculate the average of the numbers a through b rounded to nearest integer, in binary

## Python Programming Puzzles: Exercise-81 with Solution

Write a Python program to calculate the average of the numbers a through b ( b not included ) rounded to nearest integer, in binary (or -1 if there are no such numbers).

Input: 4 , 7 Output: 0b101 Input: 11 , 19 Output: 0b1110

**Pictorial Presentation:**

**Sample Solution:**

**Python Code:**

```
#License: https://bit.ly/3oLErEI
def test(a,b):
r = range(a, b)
if len(r) == 0:
return "-1"
return bin(round(sum(r) / len(r)))
a = 4
b = 7
print("Range:",a,",",b)
print("Average of the numbers",a,"through",b,"rounded to nearest integer, in binary:")
print(test(a, b))
a = 11
b = 19
print("\nRange:",a,",",b)
print("Average of the numbers",a,"through",b,"rounded to nearest integer, in binary:")
print(test(a, b))
```

Sample Output:

Range: 4 , 7 Average of the numbers 4 through 7 rounded to nearest integer, in binary: 0b101 Range: 11 , 19 Average of the numbers 11 through 19 rounded to nearest integer, in binary: 0b1110

**Flowchart:**

## Visualize Python code execution:

The following tool visualize what the computer is doing step-by-step as it executes the said program:

**Python Code Editor :**

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**Previous:** Round each float in a list of numbers up to the next integer and return the running total of the integer squares.

**Next:** Find the sublist of numbers with only odd digits in increasing order.

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## Python: Tips of the Day

**Clamps num within the inclusive range specified by the boundary values x and y:**

Example:

def tips_clamp_num(num,x,y): return max(min(num, max(x, y)), min(x, y)) print(tips_clamp_num(2, 4, 6)) print(tips_clamp_num(1, -1, -6))

Output:

4 -1

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