Python: Find the index of the matching parentheses for each character in a given string
Python Programming Puzzles: Exercise-84 with Solution
Write a Python program to find the index of the matching parentheses for each character in a given string.
Input: ()(()) Output: [1, 0, 5, 4, 3, 2] Input: ()()() Output: [1, 0, 3, 2, 5, 4] Input: ((())) Output: [5, 4, 3, 2, 1, 0]
Pictorial Presentation:


Sample Solution:
Python Code:
#License: https://bit.ly/3oLErEI
def test(parens):
a = list(parens)
stack = []
for i, c in enumerate(a):
if c == "(":
stack.append(i)
else:
a[stack[-1]] = i
a[i] = stack.pop()
return a
parens = "()(())"
print("Original parentheses:",parens)
print("Index of the matching parentheses for each character in a given string:")
print(test(parens))
parens = "()()()"
print("\nOriginal parentheses:",parens)
print("Index of the matching parentheses for each character in a given string:")
print(test(parens))
parens = "((()))"
print("\nOriginal parentheses:",parens)
print("Index of the matching parentheses for each character in a given string:")
print(test(parens))
Sample Output:
Original parentheses: ()(()) Index of the matching parentheses for each character in a given string: [1, 0, 5, 4, 3, 2] Original parentheses: ()()() Index of the matching parentheses for each character in a given string: [1, 0, 3, 2, 5, 4] Original parentheses: ((())) Index of the matching parentheses for each character in a given string: [5, 4, 3, 2, 1, 0]
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Python: Tips of the Day
Clamps num within the inclusive range specified by the boundary values x and y:
Example:
def tips_clamp_num(num,x,y): return max(min(num, max(x, y)), min(x, y)) print(tips_clamp_num(2, 4, 6)) print(tips_clamp_num(1, -1, -6))
Output:
4 -1
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