# Python: Find an integer with the given number of even and odd digits

## Python Programming Puzzles: Exercise-88 with Solution

Write a Python program to find an integer (n >= 0) with the given number of even and odd digits.

Input: Number of even digits: 2 ,Number of odd digits: 3 Output: 22333 Input: Number of even digits: 4 ,Number of odd digits: 7 Output: 22223333333

**Sample Solution:**

**Python Code:**

```
# License: https://bit.ly/3oLErEI
# Define a function named 'test' that takes two parameters 'evens' and 'odds'
def test(evens, odds):
# Generate an integer (>= 0) with the given number of even and odd digits
return int(evens * "2" + odds * "3")
# Example 1
evens1 = 2
odds1 = 3
print("Number of even digits:", evens1, ", Number of odd digits:", odds1)
print("Integer (>= 0) with the given number of even and odd digits:")
print(test(evens1, odds1))
# Example 2
evens2 = 4
odds2 = 7
print("\nNumber of even digits:", evens2, ", Number of odd digits:", odds2)
print("Integer (>= 0) with the given number of even and odd digits:")
print(test(evens2, odds2))
```

Sample Output:

Number of even digits: 2 ,Number of odd digits: 3 Integer(>= 0) with the given number of even and odd digits: 22333 Number of even digits: 4 ,Number of odd digits: 7 Integer(>= 0) with the given number of even and odd digits: 22223333333

**Flowchart:**

**Python Code Editor :**

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