Python: Find an integer with the given number of even and odd digits

Python Programming Puzzles: Exercise-88 with Solution

Write a Python program to find an integer (n >= 0) with the given number of even and odd digits.

Input: 
Number of even digits: 2 ,Number of odd digits: 3
Output:
22333

Input: 
Number of even digits: 4 ,Number of odd digits: 7
Output:
22223333333

Sample Solution:

Python Code:

#License: https://bit.ly/3oLErEI

def test(a,b):    
    return int(evens*"2"+odds*"3")   
evens = 2
odds = 3
print("Number of even digits:",evens,",Number of odd digits:",odds)
print("Integer(>= 0) with the given number of even and odd digits:")
print(test(evens, odds)) 
evens = 4
odds = 7
print("\nNumber of even digits:",evens,",Number of odd digits:",odds)
print("Integer(>= 0) with the given number of even and odd digits:")
print(test(evens, odds))

Sample Output:

Number of even digits: 2 ,Number of odd digits: 3
Integer(>= 0) with the given number of even and odd digits:
22333

Number of even digits: 4 ,Number of odd digits: 7
Integer(>= 0) with the given number of even and odd digits:
22223333333

Flowchart:

Python Code Editor :

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