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Python: Each triple of eaten, need, stock return a pair of total appetite and remaining

Python Programming Puzzles: Exercise-90 with Solution

For each triple of eaten, need, stock write a Python program to get a pair of total appetite and remaining.

Input:
[[2, 5, 6], [3, 9, 22]]
Output:
[[7, 1], [12, 13]]

Input:
[[2, 3, 18], [4, 9, 2], [2, 5, 7], [3, 8, 12], [4, 9, 106]]
Output:
[[5, 15], [6, 0], [7, 2], [11, 4], [13, 97]]

Input:
[[1, 2, 3], [4, 5, 6]]
Output:
[[3, 1], [9, 1]]

Sample Solution:

Python Code:

 #License: https://bit.ly/3oLErEI

def test(nums):
    return [[a+min(b, c), max(0, c-b)] for a, b, c in nums]

nums = [[2, 5, 6], [3, 9, 22]]
print("Original list (triple) of lists:")
print(nums)
print("Each triple of eaten, need, stock return a pair of total appetite and remaining:")
print(test(nums))
nums = [[2, 3, 18], [4, 9, 2], [2, 5, 7], [3, 8, 12], [4, 9, 106]]
print("\nOriginal list (triple) of lists:")
print(nums)
print("Each triple of eaten, need, stock return a pair of total appetite and remaining:")
print(test(nums)) 
nums = [[1, 2, 3], [4, 5, 6]]
print("\nOriginal list (triple) of lists:")
print(nums)
print("Each triple of eaten, need, stock return a pair of total appetite and remaining:")
print(test(nums))

Sample Output:

Original list (triple) of lists:
[[2, 5, 6], [3, 9, 22]]
Each triple of eaten, need, stock return a pair of total appetite and remaining:
[[7, 1], [12, 13]]

Original list (triple) of lists:
[[2, 3, 18], [4, 9, 2], [2, 5, 7], [3, 8, 12], [4, 9, 106]]
Each triple of eaten, need, stock return a pair of total appetite and remaining:
[[5, 15], [6, 0], [7, 2], [11, 4], [13, 97]]

Original list (triple) of lists:
[[1, 2, 3], [4, 5, 6]]
Each triple of eaten, need, stock return a pair of total appetite and remaining:
[[3, 1], [9, 1]]

Flowchart:

Flowchart: Python - Each triple of eaten, need, stock return a pair of total appetite and remaining.

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Python Code Editor :

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Python: Tips of the Day

Clamps num within the inclusive range specified by the boundary values x and y:

Example:

def tips_clamp_num(num,x,y):
  return max(min(num, max(x, y)), min(x, y))
print(tips_clamp_num(2, 4, 6))
print(tips_clamp_num(1, -1, -6))

Output:

4
-1