﻿ Python: Convert pressure in kilopascals to pounds - w3resource

# Python: Convert pressure in kilopascals to pounds

## Python Basic: Exercise-67 with Solution

Write a Python program to convert pressure in kilopascals to pounds per square inch,a millimeter of mercury (mmHg) and atmosphere pressure.

Pictorial Presentation: Sample Solution-1:

Python Code:

``````kpa = float(input("Input pressure in in kilopascals> "))
psi = kpa / 6.89475729
mmhg = kpa * 760 / 101.325
atm = kpa / 101.325
print("The pressure in pounds per square inch: %.2f psi"  % (psi))
print("The pressure in millimeter of mercury: %.2f mmHg" % (mmhg))
print("Atmosphere pressure: %.2f atm." % (atm))
```
```

Sample Output:

```Input pressure in in kilopascals> 12.35
The pressure in pounds per square inch: 1.79 psi
The pressure in millimeter of mercury: 92.63 mmHg
Atmosphere pressure: 0.12 atm.
```

## Visualize Python code execution:

The following tool visualize what the computer is doing step-by-step as it executes the said program:

Sample Solution-2:

Python Code:

``````kpa= float(input("Input the pressure in kilopascals > "))
pressure_in_psi = round(kpa * 0.145038,3)
pressure_in_mmHg = round(kpa * 7.50062, 3)
pressure_in_atmp = round(kpa * 0.0098692382432766,3)
print(f"Pressure = {pressure_in_psi} psi \nor {pressure_in_mmHg} mmHg \nor {pressure_in_atmp} atmp")
```
```

Sample Output:

```Input the pressure in kilopascals >  12.35
Pressure = 1.791 psi
or 92.633 mmHg
or 0.122 atmp
```

Python Code Editor:

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## Python: Tips of the Day

Creates a dictionary with the same keys as the provided dictionary and values generated by running the provided function for each value:

Example:

```def tips_map_values(obj, fn):
ret = {}
for key in obj.keys():
ret[key] = fn(obj[key])
return ret
users = {
'Owen': { 'user': 'Owen', 'age': 29 },
'Eddie': { 'user': 'Eddie', 'age': 15 }
}

print(tips_map_values(users, lambda u : u['age'])) # {'Owen': 29, 'Eddie': 15}
```

Output:

```{'Owen': 29, 'Eddie': 15}
```

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