Python: Convert pressure in kilopascals to pounds
Python Basic: Exercise-67 with Solution
Write a Python program to convert pressure in kilopascals to pounds per square inch,a millimeter of mercury (mmHg) and atmosphere pressure.
Pictorial Presentation:

Sample Solution-1:
Python Code:
kpa = float(input("Input pressure in in kilopascals> "))
psi = kpa / 6.89475729
mmhg = kpa * 760 / 101.325
atm = kpa / 101.325
print("The pressure in pounds per square inch: %.2f psi" % (psi))
print("The pressure in millimeter of mercury: %.2f mmHg" % (mmhg))
print("Atmosphere pressure: %.2f atm." % (atm))
Sample Output:
Input pressure in in kilopascals> 12.35 The pressure in pounds per square inch: 1.79 psi The pressure in millimeter of mercury: 92.63 mmHg Atmosphere pressure: 0.12 atm.
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Sample Solution-2:
Python Code:
kpa= float(input("Input the pressure in kilopascals > "))
pressure_in_psi = round(kpa * 0.145038,3)
pressure_in_mmHg = round(kpa * 7.50062, 3)
pressure_in_atmp = round(kpa * 0.0098692382432766,3)
print(f"Pressure = {pressure_in_psi} psi \nor {pressure_in_mmHg} mmHg \nor {pressure_in_atmp} atmp")
Sample Output:
Input the pressure in kilopascals > 12.35 Pressure = 1.791 psi or 92.633 mmHg or 0.122 atmp
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Python: Tips of the Day
Creates a dictionary with the same keys as the provided dictionary and values generated by running the provided function for each value:
Example:
def tips_map_values(obj, fn): ret = {} for key in obj.keys(): ret[key] = fn(obj[key]) return ret users = { 'Owen': { 'user': 'Owen', 'age': 29 }, 'Eddie': { 'user': 'Eddie', 'age': 15 } } print(tips_map_values(users, lambda u : u['age'])) # {'Owen': 29, 'Eddie': 15}
Output:
{'Owen': 29, 'Eddie': 15}
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