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Python Exercise: Get Fizz, Buzz and FizzBuzz

Python Conditional: Exercise-10 with Solution

Write a Python program that iterates the integers from 1 to 50. For multiples of three print "Fizz" instead of the number and for multiples of five print "Buzz". For numbers that are multiples of three and five, print "FizzBuzz".

Sample Solution:

Python Code :

for fizzbuzz in range(51):
    if fizzbuzz % 3 == 0 and fizzbuzz % 5 == 0:
        print("fizzbuzz")
        continue
    elif fizzbuzz % 3 == 0:
        print("fizz")
        continue
    elif fizzbuzz % 5 == 0:
        print("buzz")
        continue
    print(fizzbuzz)
	

Sample Output:

fizzbuzz
1
2
fizz
4
buzz
fizz
7
8
fizz
buzz
11
fizz
13
14
fizzbuzz
 ..... 
 
41
fizz
43
44
fizzbuzz
46
47
fizz
49
buzz

Flowchart:

Flowchart: Python program to get Fizz, Buzz and FizzBuzz

Visualize Python code execution:

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Python Code Editor :

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Previous: Write a Python program to get the Fibonacci series between 0 to 50.
Next: Write a Python program which takes two digits m (row) and n (column) as input and generates a two-dimensional array. The element value in the i-th row and j-th column of the array should be i*j.

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Python: Tips of the Day

Returns the difference between two lists, after applying the provided function to each list element of both:

Example:

def difference_by(a, b, fn):
  _b = set(map(fn, b))
  return [item for item in a if fn(item) not in _b]

from math import floor
print(difference_by([2.1, 1.2], [2.3, 3.4], floor))
print(difference_by([{ 'x': 2 }, { 'x': 1 }], [{ 'x': 1 }], lambda v : v['x']))

Output:

[1.2]
[{'x': 2}]