w3resource

Python Exercise: Print alphabet pattern G

Python Conditional: Exercise - 20 with Solution

Write a Python program to print alphabet pattern 'G'.

Pictorial Presentation:

Python Exercise: Print alphabet pattern G

Sample Solution:

Python Code:

result_str="";    
for row in range(0,7):    
    for column in range(0,7):     
        if ((column == 1 and row != 0 and row != 6) or ((row == 0 or row == 6) and column > 1 and column < 5) or (row == 3 and column > 2 and column < 6) or (column == 5 and row != 0 and row != 2 and row != 6)):  
            result_str=result_str+"*"    
        else:      
            result_str=result_str+" "    
    result_str=result_str+"\n"    
print(result_str);

Sample Output:

  ***                                                                                                         
 *   *                                                                                                        
 *                                                                                                            
 * ***                                                                                                        
 *   *                                                                                                        
 *   *                                                                                                        
  ***    

Flowchart:

Flowchart: Print alphabet pattern G

Visualize Python code execution:

The following tool visualize what the computer is doing step-by-step as it executes the said program:

Python Code Editor:

Have another way to solve this solution? Contribute your code (and comments) through Disqus.

Previous: Write a Python program to print alphabet pattern 'E'.
Next: Write a Python program to print alphabet pattern 'L'.

What is the difficulty level of this exercise?

Test your Python skills with w3resource's quiz



Python: Tips of the Day

Returns a list with n elements removed from the beginning

Example:

def tips_take(itr, n = 1):
  return itr[:n]
print(tips_take([1, 2, 3], 5))
print(tips_take([1, 2, 3], 0))

Output:

[1, 2, 3]
[]