Python: Matches a word at the end of a string, with optional punctuation

Last update on April 23 2025 12:59:51 (UTC/GMT +8 hours)

11. Word at End

Write a Python program that matches a word at the end of a string, with optional punctuation.

Sample Solution:

Python Code:

import re
def text_match(text):
        patterns = '\w+\S*$'
        if re.search(patterns,  text):
                return 'Found a match!'
        else:
                return('Not matched!')

print(text_match("The quick brown fox jumps over the lazy dog."))
print(text_match("The quick brown fox jumps over the lazy dog. "))
print(text_match("The quick brown fox jumps over the lazy dog "))

Sample Output:

Found a match!                                                                                                
Not matched!                                                                                                  
Not matched!

Pictorial Presentation:

Flowchart:

For more Practice: Solve these Related Problems:

• Write a Python program to check if a string ends with a specific word, allowing for optional punctuation.
• Write a Python script to extract the last word of a sentence even if it ends with punctuation.
• Write a Python program to match a pattern that confirms a string’s ending word, regardless of trailing punctuation.
• Write a Python program to verify if the final word in a string matches a given pattern and output its position.

Go to:

• Python Regular Expression Exercises Home ↩
• Python Exercises Home ↩

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Python Code Editor:

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