﻿ Python: Match if two words from a list of words starting with letter 'P' - w3resource

Python: Match if two words from a list of words starting with letter 'P'

Python Regular Expression: Exercise-26 with Solution

Write a Python program to match if two words from a list of words starting with letter 'P'.

Sample Solution:-

Python Code:

``````import re

# Sample strings.
words = ["Python PHP", "Java JavaScript", "c c++"]

for w in words:
m = re.match("(P\w+)\W(P\w+)", w)
# Check for success
if m:
print(m.groups())
```
```

Sample Output:

```('Python', 'PHP')
```

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Python: Tips of the Day

Getting the last element of a list:

some_list[-1] is the shortest and most Pythonic.

In fact, you can do much more with this syntax. The some_list[-n] syntax gets the nth-to-last element. So some_list[-1] gets the last element, some_list[-2] gets the second to last, etc, all the way down to some_list[-len(some_list)], which gives you the first element.

You can also set list elements in this way. For instance:

```>>> some_list = [1, 2, 3]
>>> some_list[-1] = 5 # Set the last element
>>> some_list[-2] = 3 # Set the second to last element
>>> some_list
[1, 3, 5]
```

Note that getting a list item by index will raise an IndexError if the expected item doesn't exist. This means that some_list[-1] will raise an exception if some_list is empty, because an empty list can't have a last element.

Ref: https://bit.ly/3d8TfFP