﻿ Python: Check if a set is a subset of another set - w3resource

# Python: Check if a set is a subset of another set

## Python sets: Exercise-10 with Solution

Write a Python program to check if a set is a subset of another set.

From Wikipedia,
In mathematics, a set A is a subset of a set B if all elements of A are also elements of B; B is then a superset of A. It is possible for A and B to be equal; if they are unequal, then A is a proper subset of B. The relationship of one set being a subset of another is called inclusion (or sometimes containment). A is a subset of B may also be expressed as B includes (or contains) A or A is included (or contained) in B.

Sample Solution:

Python Code:

``````print("Check if a set is a subset of another set, using comparison operators and issubset():\n")
setx = set(["apple", "mango"])
sety = set(["mango", "orange"])
setz = set(["mango"])
print("x: ",setx)
print("y: ",sety)
print("z: ",setz,"\n")
print("If x is subset of y")
print(setx <= sety)
print(setx.issubset(sety))
print("If y is subset of x")
print(sety <= setx)
print(sety.issubset(setx))
print("\nIf y is subset of z")
print(sety <= setz)
print(sety.issubset(setz))
print("If z is subset of y")
print(setz <= sety)
print(setz.issubset(sety))
```
```

Sample Output:

```Check if a set is a subset of another set, using comparison operators and issubset():

x:  {'mango', 'apple'}
y:  {'mango', 'orange'}
z:  {'mango'}

If x is subset of y
False
False
If y is subset of x
False
False

If y is subset of z
False
False
If z is subset of y
True
True
```

Pictorial Presentation:

## Visualize Python code execution:

The following tool visualize what the computer is doing step-by-step as it executes the said program:

Python Code Editor:

Have another way to solve this solution? Contribute your code (and comments) through Disqus.

What is the difficulty level of this exercise?

Test your Programming skills with w3resource's quiz.

﻿

## Python: Tips of the Day

Inserting if statements using conditional list comprehensions:

```x = [1, 2, 3, 4, 5, 6]
result = []
for idx in range(len(x)):
if x[idx] % 2 == 0:
result.append(x[idx] * 2)
else:
result.append(x[idx])
result
```

Output:

```[1, 4, 3, 8, 5, 12]
```
`[(element * 2 if element % 2 == 0 else element) for element in x]`

Output:

```[1, 4, 3, 8, 5, 12]
```
`[element * 2 for element in x if element % 2 == 0]`

Output:

```[4, 8, 12]
```