Python: Create a SQLite database and connect with the database and print the version of the SQLite database

Last update on April 24 2025 12:40:27 (UTC/GMT +8 hours)

1. SQLite DB Version

Write a Python program to create a SQLite database and connect with the database and print the version of the SQLite database.

Sample Solution:

Python Code :

import sqlite3
try:
   sqlite_Connection = sqlite3.connect('temp.db')
   conn = sqlite_Connection.cursor()
   print("\nDatabase created and connected to SQLite.")
   sqlite_select_Query = "select sqlite_version();"
   conn.execute(sqlite_select_Query)
   record = conn.fetchall()
   print("\nSQLite Database Version is: ", record)
   conn.close()
except sqlite3.Error as error:
   print("\nError while connecting to sqlite", error)
finally:
   if (sqlite_Connection):
       sqlite_Connection.close()
       print("\nThe SQLite connection is closed.")

Sample Output:

Database created and connected to SQLite.

SQLite Database Version is:  [('3.11.0',)]

The SQLite connection is closed.

Alternate solution (Connect to a SQLite Database):

Python Code :

import  sqlite3
print("creating connecting ...")
conn  =  sqlite3.connect ('mydatabase.db' )
conn . close ()
print("\nThe SQLite connection is closed.")

Sample Output:

creating connecting ...

The SQLite connection is closed.

For more Practice: Solve these Related Problems:

Write a Python program that creates a SQLite database file, connects to it, retrieves the SQLite version using a SQL query, and prints it.
Write a Python script to create a new SQLite database, execute a query to get the version, and log the version information to a text file.
Write a Python function that establishes a SQLite connection, executes a "SELECT sqlite_version()" query, and returns the version as a string.
Write a Python program that creates a SQLite database, prints its version, and then compares the version to a minimum required version, printing a warning if outdated.

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Python Code Editor:

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