Python: Format a number with a percentage

Python String: Exercise-36 with Solution

Write a Python program to format a number with a percentage.

Python String Exercises: Format a number with a percentage

Sample Solution:-

Python Code:

x = 0.25
y = -0.25
print("\nOriginal Number: ", x)
print("Formatted Number with percentage: "+"{:.2%}".format(x));
print("Original Number: ", y)
print("Formatted Number with percentage: "+"{:.2%}".format(y));

Sample Output:

Original Number:  0.25                                                                                        
Formatted Number with percentage: 25.00%                                                                      
Original Number:  -0.25                                                                                       
Formatted Number with percentage: -25.00% 


Flowchart: Format a number with percentage

Visualize Python code execution:

The following tool visualize what the computer is doing step-by-step as it executes the said program:

Python Code Editor:

Have another way to solve this solution? Contribute your code (and comments) through Disqus.

Previous: Write a Python program to display a number with a comma separator.
Next: Write a Python program to display a number in left, right and center aligned of width 10.

What is the difficulty level of this exercise?

Test your Programming skills with w3resource's quiz.

Python: Tips of the Day

Check if a given key already exists in a dictionary:

In is the intended way to test for the existence of a key in a dict.

d = {"key1": 10, "key2": 23}

if "key1" in d:
    print("this will execute")

if "nonexistent key" in d:
    print("this will not")

If you wanted a default, you can always use dict.get():

d = dict()

for i in range(100):
    key = i % 10
    d[key] = d.get(key, 0) + 1

and if you wanted to always ensure a default value for any key you can either use dict.setdefault() repeatedly or defaultdict from the collections module, like so:

from collections import defaultdict

d = defaultdict(int)

for i in range(100):
    d[i % 10] += 1

but in general, the in keyword is the best way to do it.

Ref: https://bit.ly/2XPMRyz