Python: Find the first repeated character of a given string where the index of first occurrence is smallest
Python String: Exercise-54 with Solution
Write a Python program to find the first repeated character of a given string where the index of first occurrence is smallest.
Sample Solution:-
Python Code:
def first_repeated_char_smallest_distance(str1):
temp = {}
for ch in str1:
if ch in temp:
return ch, str1.index(ch);
else:
temp[ch] = 0
return 'None'
print(first_repeated_char_smallest_distance("abcabc"))
print(first_repeated_char_smallest_distance("abcb"))
print(first_repeated_char_smallest_distance("abcc"))
print(first_repeated_char_smallest_distance("abcxxy"))
print(first_repeated_char_smallest_distance("abc"))))
Sample Output:
('a', 0) ('b', 1) ('c', 2) ('x', 3) None
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Python: Tips of the Day
Check if a given key already exists in a dictionary:
In is the intended way to test for the existence of a key in a dict.
d = {"key1": 10, "key2": 23} if "key1" in d: print("this will execute") if "nonexistent key" in d: print("this will not")
If you wanted a default, you can always use dict.get():
d = dict() for i in range(100): key = i % 10 d[key] = d.get(key, 0) + 1
and if you wanted to always ensure a default value for any key you can either use dict.setdefault() repeatedly or defaultdict from the collections module, like so:
from collections import defaultdict d = defaultdict(int) for i in range(100): d[i % 10] += 1
but in general, the in keyword is the best way to do it.
Ref: https://bit.ly/2XPMRyz
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