﻿ Python: Find maximum length of consecutive 0’s in a given binary string - w3resource

# Python: Find maximum length of consecutive 0’s in a given binary string

## Python String: Exercise-64 with Solution

Write a Python program to find maximum length of consecutive 0’s in a given binary string.

Sample Solution:-

Python Code:

``````def max_consecutive_0(input_str):
return  max(map(len,input_str.split('1')))
str1 = '111000010000110'
print("Original string:" + str1)
print("Maximum length of consecutive 0’s:")
print(max_consecutive_0(str1))
str1 = '111000111'
print("Original string:" + str1)
print("Maximum length of consecutive 0’s:")
print(max_consecutive_0(str1))
```
```

Sample Output:

```Original string:111000010000110
Maximum length of consecutive 0’s:
4
Original string:111000111
Maximum length of consecutive 0’s:
3
```

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Flowchart:

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## Python: Tips of the Day

Check if a given key already exists in a dictionary:

In is the intended way to test for the existence of a key in a dict.

```d = {"key1": 10, "key2": 23}

if "key1" in d:
print("this will execute")

if "nonexistent key" in d:
print("this will not")
```

If you wanted a default, you can always use dict.get():

```d = dict()

for i in range(100):
key = i % 10
d[key] = d.get(key, 0) + 1
```

and if you wanted to always ensure a default value for any key you can either use dict.setdefault() repeatedly or defaultdict from the collections module, like so:

```from collections import defaultdict

d = defaultdict(int)

for i in range(100):
d[i % 10] += 1
```

but in general, the in keyword is the best way to do it.

Ref: https://bit.ly/2XPMRyz