Python: Find the minimum window in a given string which will contain all the characters of another given string
Python String: Exercise-74 with Solution
Write a Python program to find the minimum window in a given string which will contain all the characters of another given string.
Example 1
Input
str1 = " PRWSOERIUSFK "
str2 = " OSU "
Output:
Minimum window is "OERIUS"
Sample Solution:
Python Code:
import collections
def min_window(str1, str2):
result_char, missing_char = collections.Counter(str2), len(str2)
i = p = q = 0
for j, c in enumerate(str1, 1):
missing_char -= result_char[c] > 0
result_char[c] -= 1
if not missing_char:
while i < q and result_char[str1[i]] < 0:
result_char[str1[i]] += 1
i += 1
if not q or j - i <= q - p:
p, q = i, j
return str1[p:q]
str1 = "PRWSOERIUSFK"
str2 = "OSU"
print("Original Strings:\n",str1,"\n",str2)
print("Minimum window:")
print(min_window(str1,str2))
Sample Output:
Original Strings: PRWSOERIUSFK OSU Minimum window: OERIUS
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Python: Tips of the Day
Check if a given key already exists in a dictionary:
In is the intended way to test for the existence of a key in a dict.
d = {"key1": 10, "key2": 23} if "key1" in d: print("this will execute") if "nonexistent key" in d: print("this will not")
If you wanted a default, you can always use dict.get():
d = dict() for i in range(100): key = i % 10 d[key] = d.get(key, 0) + 1
and if you wanted to always ensure a default value for any key you can either use dict.setdefault() repeatedly or defaultdict from the collections module, like so:
from collections import defaultdict d = defaultdict(int) for i in range(100): d[i % 10] += 1
but in general, the in keyword is the best way to do it.
Ref: https://bit.ly/2XPMRyz
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