﻿ Python: Find smallest and largest word in a given string - w3resource

# Python: Find smallest and largest word in a given string

## Python String: Exercise-79 with Solution

Write a Python program to find smallest and largest word in a given string.

Sample Solution:-

Python Code:

``````def smallest_largest_words(str1):
word = "";
all_words = [];
str1 = str1 + " ";
for i in range(0, len(str1)):
if(str1[i] != ' '):
word = word + str1[i];
else:
all_words.append(word);
word = "";

small = large = all_words[0];

#Find smallest and largest word in the str1
for k in range(0, len(all_words)):
if(len(small) > len(all_words[k])):
small = all_words[k];
if(len(large) < len(all_words[k])):
large = all_words[k];
return small,large;

str1 = "Write a Java program to sort an array of given integers using Quick sort Algorithm.";
print("Original Strings:\n",str1)
small, large = smallest_largest_words(str1)
print("Smallest word: " + small);
print("Largest word: " + large);
```
```

Sample Output:

```Original Strings:
Write a Java program to sort an array of given integers using Quick sort Algorithm.
Smallest word: a
Largest word: Algorithm.
```

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## Python: Tips of the Day

Check if a given key already exists in a dictionary:

In is the intended way to test for the existence of a key in a dict.

```d = {"key1": 10, "key2": 23}

if "key1" in d:
print("this will execute")

if "nonexistent key" in d:
print("this will not")
```

If you wanted a default, you can always use dict.get():

```d = dict()

for i in range(100):
key = i % 10
d[key] = d.get(key, 0) + 1
```

and if you wanted to always ensure a default value for any key you can either use dict.setdefault() repeatedly or defaultdict from the collections module, like so:

```from collections import defaultdict

d = defaultdict(int)

for i in range(100):
d[i % 10] += 1
```

but in general, the in keyword is the best way to do it.

Ref: https://bit.ly/2XPMRyz