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Python: Find smallest and largest word in a given string

Python String: Exercise-79 with Solution

Write a Python program to find smallest and largest word in a given string.

Sample Solution:-

Python Code:

def smallest_largest_words(str1):
    word = "";
    all_words = [];
    str1 = str1 + " ";
    for i in range(0, len(str1)):
        if(str1[i] != ' '):
            word = word + str1[i];  
        else:
            all_words.append(word);  
            word = "";  
          
    small = large = all_words[0];  
   
#Find smallest and largest word in the str1  
    for k in range(0, len(all_words)):
        if(len(small) > len(all_words[k])):
            small = all_words[k];
        if(len(large) < len(all_words[k])):
            large = all_words[k];
    return small,large;

str1 = "Write a Java program to sort an array of given integers using Quick sort Algorithm.";  
print("Original Strings:\n",str1)
small, large = smallest_largest_words(str1)  
print("Smallest word: " + small);  
print("Largest word: " + large); 

Sample Output:

Original Strings:
 Write a Java program to sort an array of given integers using Quick sort Algorithm.
Smallest word: a
Largest word: Algorithm.

Pictorial Presentation:

Python String: Find smallest and largest word in a given string.

Flowchart:

Flowchart: Find smallest and largest word in a given string

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Previous: Write a Python program to count characters at same position in a given string (lower and uppercase characters) as in English alphabet.
Next: Write a Python program to count number of substrings with same first and last characters of a given string.

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Python: Tips of the Day

Check if a given key already exists in a dictionary:

In is the intended way to test for the existence of a key in a dict.

d = {"key1": 10, "key2": 23}

if "key1" in d:
    print("this will execute")

if "nonexistent key" in d:
    print("this will not")

If you wanted a default, you can always use dict.get():

d = dict()

for i in range(100):
    key = i % 10
    d[key] = d.get(key, 0) + 1

and if you wanted to always ensure a default value for any key you can either use dict.setdefault() repeatedly or defaultdict from the collections module, like so:

from collections import defaultdict

d = defaultdict(int)

for i in range(100):
    d[i % 10] += 1

but in general, the in keyword is the best way to do it.

Ref: https://bit.ly/2XPMRyz