Python: Find smallest and largest word in a given string
Python String: Exercise-79 with Solution
Write a Python program to find smallest and largest word in a given string.
Sample Solution:-
Python Code:
def smallest_largest_words(str1):
word = "";
all_words = [];
str1 = str1 + " ";
for i in range(0, len(str1)):
if(str1[i] != ' '):
word = word + str1[i];
else:
all_words.append(word);
word = "";
small = large = all_words[0];
#Find smallest and largest word in the str1
for k in range(0, len(all_words)):
if(len(small) > len(all_words[k])):
small = all_words[k];
if(len(large) < len(all_words[k])):
large = all_words[k];
return small,large;
str1 = "Write a Java program to sort an array of given integers using Quick sort Algorithm.";
print("Original Strings:\n",str1)
small, large = smallest_largest_words(str1)
print("Smallest word: " + small);
print("Largest word: " + large);
Sample Output:
Original Strings: Write a Java program to sort an array of given integers using Quick sort Algorithm. Smallest word: a Largest word: Algorithm.
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Previous: Write a Python program to count characters at same position in a given string (lower and uppercase characters) as in English alphabet.
Next: Write a Python program to count number of substrings with same first and last characters of a given string.
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Python: Tips of the Day
Check if a given key already exists in a dictionary:
In is the intended way to test for the existence of a key in a dict.
d = {"key1": 10, "key2": 23} if "key1" in d: print("this will execute") if "nonexistent key" in d: print("this will not")
If you wanted a default, you can always use dict.get():
d = dict() for i in range(100): key = i % 10 d[key] = d.get(key, 0) + 1
and if you wanted to always ensure a default value for any key you can either use dict.setdefault() repeatedly or defaultdict from the collections module, like so:
from collections import defaultdict d = defaultdict(int) for i in range(100): d[i % 10] += 1
but in general, the in keyword is the best way to do it.
Ref: https://bit.ly/2XPMRyz
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