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Python: Takes a list of words and returns the length of the longest one

Python String: Exercise-8 with Solution

Write a Python function that takes a list of words and return the longest word and the length of the longest one.

Python String Exercises: Takes a list of words and return the length of the longest one

Sample Solution:-

Python Code:

def find_longest_word(words_list):
    word_len = []
    for n in words_list:
        word_len.append((len(n), n))
    word_len.sort()
    return word_len[-1][0], word_len[-1][1]
result = find_longest_word(["PHP", "Exercises", "Backend"])
print("\nLongest word: ",result[1])
print("Length of the longest word: ",result[0])

Sample Output:

Longest word:  Exercises
Length of the longest word:  9

Flowchart:

Flowchart: Function that takes a list of words and return the length of the longest one

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Previous: Write a Python program to find the first appearance of the substring 'not' and 'poor' from a given string, if 'bad' follows the 'poor', replace the whole 'not'...'poor' substring with 'good'. Return the resulting string.
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Python: Tips of the Day

Check if a given key already exists in a dictionary:

In is the intended way to test for the existence of a key in a dict.

d = {"key1": 10, "key2": 23}

if "key1" in d:
    print("this will execute")

if "nonexistent key" in d:
    print("this will not")

If you wanted a default, you can always use dict.get():

d = dict()

for i in range(100):
    key = i % 10
    d[key] = d.get(key, 0) + 1

and if you wanted to always ensure a default value for any key you can either use dict.setdefault() repeatedly or defaultdict from the collections module, like so:

from collections import defaultdict

d = defaultdict(int)

for i in range(100):
    d[i % 10] += 1

but in general, the in keyword is the best way to do it.

Ref: https://bit.ly/2XPMRyz