﻿ Python: Print four values decimal, octal, hexadecimal, binary in a single line of a given integer - w3resource

# Python: Print four values decimal, octal, hexadecimal, binary in a single line of a given integer

## Python String: Exercise-83 with Solution

Write a Python program to print four values decimal, octal, hexadecimal (capitalized), binary in a single line of a given integer.

Sample Solution:-

Python Code:

``````i = int(input("Input an integer: "))
o = str(oct(i))[2:]
h = str(hex(i))[2:]
h = h.upper()
b = str(bin(i))[2:]
d = str(i)
print(d,'  ',o,' ',h,'                   ',b)
```
```

Sample Output:

```Input an integer:  25
25    31   19                     11001
```

Flowchart:

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## Python: Tips of the Day

Check if a given key already exists in a dictionary:

In is the intended way to test for the existence of a key in a dict.

```d = {"key1": 10, "key2": 23}

if "key1" in d:
print("this will execute")

if "nonexistent key" in d:
print("this will not")
```

If you wanted a default, you can always use dict.get():

```d = dict()

for i in range(100):
key = i % 10
d[key] = d.get(key, 0) + 1
```

and if you wanted to always ensure a default value for any key you can either use dict.setdefault() repeatedly or defaultdict from the collections module, like so:

```from collections import defaultdict

d = defaultdict(int)

for i in range(100):
d[i % 10] += 1
```

but in general, the in keyword is the best way to do it.

Ref: https://bit.ly/2XPMRyz