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Python: Convert a given Bytearray to Hexadecimal string

Python String: Exercise-85 with Solution

Write a Python program to convert a given Bytearray to Hexadecimal string.

Sample Solution:-

Python Code:

def bytearray_to_hexadecimal(list_val):
     result = ''.join('{:02x}'.format(x) for x in list_val)  
     return(result)

list_val = [111, 12, 45, 67, 109] 
print("Original Bytearray :")
print(list_val)
print("\nHexadecimal string:")
print(bytearray_to_hexadecimal(list_val))

Sample Output:

Original Bytearray :
[111, 12, 45, 67, 109]

Hexadecimal string:
6f0c2d436d

Flowchart:

Flowchart: Convert a given Bytearray to Hexadecimal string.

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Python Code Editor:

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Python: Tips of the Day

Check if a given key already exists in a dictionary:

In is the intended way to test for the existence of a key in a dict.

d = {"key1": 10, "key2": 23}

if "key1" in d:
    print("this will execute")

if "nonexistent key" in d:
    print("this will not")

If you wanted a default, you can always use dict.get():

d = dict()

for i in range(100):
    key = i % 10
    d[key] = d.get(key, 0) + 1

and if you wanted to always ensure a default value for any key you can either use dict.setdefault() repeatedly or defaultdict from the collections module, like so:

from collections import defaultdict

d = defaultdict(int)

for i in range(100):
    d[i % 10] += 1

but in general, the in keyword is the best way to do it.

Ref: https://bit.ly/2XPMRyz