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Python: Convert a given heterogeneous list of scalars into a string

Python String: Exercise-91 with Solution

Write a Python program to convert a given heterogeneous list of scalars into a string.

Sample Solution:-

Python Code:

def heterogeneous_list_to_str(lst):
    result = ','.join(str(x) for x in lst)
    return result
h_data = ["Red", 100, -50, "green", "w,3,r", 12.12, False]
print("Original list:")
print(h_data)
print("\nConvert the heterogeneous list of scalars into a string:")
print(heterogeneous_list_to_str(h_data))

Sample Output:

Original list:
['Red', 100, -50, 'green', 'w,3,r', 12.12, False]

Convert the heterogeneous list of scalars into a string:
Red,100,-50,green,w,3,r,12.12,False

Flowchart:

Flowchart: Convert a given heterogeneous list of scalars into a string.

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Python: Tips of the Day

Check if a given key already exists in a dictionary:

In is the intended way to test for the existence of a key in a dict.

d = {"key1": 10, "key2": 23}

if "key1" in d:
    print("this will execute")

if "nonexistent key" in d:
    print("this will not")

If you wanted a default, you can always use dict.get():

d = dict()

for i in range(100):
    key = i % 10
    d[key] = d.get(key, 0) + 1

and if you wanted to always ensure a default value for any key you can either use dict.setdefault() repeatedly or defaultdict from the collections module, like so:

from collections import defaultdict

d = defaultdict(int)

for i in range(100):
    d[i % 10] += 1

but in general, the in keyword is the best way to do it.

Ref: https://bit.ly/2XPMRyz