Python: Convert a given heterogeneous list of scalars into a string
Python String: Exercise-91 with Solution
Write a Python program to convert a given heterogeneous list of scalars into a string.
Sample Solution:-
Python Code:
def heterogeneous_list_to_str(lst):
result = ','.join(str(x) for x in lst)
return result
h_data = ["Red", 100, -50, "green", "w,3,r", 12.12, False]
print("Original list:")
print(h_data)
print("\nConvert the heterogeneous list of scalars into a string:")
print(heterogeneous_list_to_str(h_data))
Sample Output:
Original list: ['Red', 100, -50, 'green', 'w,3,r', 12.12, False] Convert the heterogeneous list of scalars into a string: Red,100,-50,green,w,3,r,12.12,False
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Python: Tips of the Day
Check if a given key already exists in a dictionary:
In is the intended way to test for the existence of a key in a dict.
d = {"key1": 10, "key2": 23} if "key1" in d: print("this will execute") if "nonexistent key" in d: print("this will not")
If you wanted a default, you can always use dict.get():
d = dict() for i in range(100): key = i % 10 d[key] = d.get(key, 0) + 1
and if you wanted to always ensure a default value for any key you can either use dict.setdefault() repeatedly or defaultdict from the collections module, like so:
from collections import defaultdict d = defaultdict(int) for i in range(100): d[i % 10] += 1
but in general, the in keyword is the best way to do it.
Ref: https://bit.ly/2XPMRyz
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