Rust Program: Printing even numbers

Rust Basic: Exercise-8 with Solution

Write a Rust program that prints all even numbers from 1 to 20 using a while loop.

Sample Solution:

Rust Code:

fn main() {
    // Initialize a variable to start counting from
    let mut count = 1;

    // Start a loop that runs until count reaches 20
    while count <= 20 {
        // Check if the current number is even
        if count % 2 == 0 {
            // Print the current even number
            println!("Even number: {}", count);
        }

        // Increment count by 1
        count += 1;
    }
}

Output:

Even number: 2
Even number: 4
Even number: 6
Even number: 8
Even number: 10
Even number: 12
Even number: 14
Even number: 16
Even number: 18
Even number: 20

Explanation:

Here's a brief explanation of the above Rust code:

• fn main() { ... }: This is the entry point of the program, where execution begins.
• let mut count = 1;: This line declares a mutable variable named 'count' and initializes it with the value 1.
• while count <= 20 { ... }: This line starts a "while" loop. The loop will continue executing as long as the condition count <= 20 evaluates to 'true'.
• if count % 2 0 { ... }: This line starts an "if" statement. If the condition count % 2 0 evaluates to 'true', it means that the current value of 'count' is even.
• println!("Even number: {}", count);: This line prints the current value of the 'count' variable using the println! macro. The {} is a placeholder for the value of 'count', which is provided as an argument to the println! macro.
• count += 1;: This line increments the value of the 'count' variable by 1. After each iteration of the loop, the value of 'count' will be increased by 1.

Rust Code Editor:

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