Rust Program: Iterate over array and print elements

Rust Variables and Data Types: Exercise-8 with Solution

Write a Rust program that creates an array of numbers containing 5 integers. Iterate over the array and print each element.

Sample Solution:

Rust Code:

fn main() {
    // Define an array of 5 integers
    let numbers = [1, 2, 3, 4, 5];

    // Iterate over the array and print each element
    for &number in numbers.iter() {
        println!("{}", number);
    }
}

Output:

1
2
3
4
5

Explanation:

The above Rust code defines a main function that demonstrates how to iterate over an array of integers and print each element.

• fn main() { ... }: This declares the main function, which serves as the entry point of the program.
• let numbers = [1, 2, 3, 4, 5];: This line defines an array named 'numbers' containing five integers: 1, 2, 3, 4, and 5.
• for &number in numbers.iter() { ... }: This is a for loop that iterates over each element of the 'numbers' array using the "iter()" method. The loop variable '&number' is a reference to each element of the array. The '&' symbol before 'number' indicates that we are iterating over references to the elements rather than the elements themselves. This is because array elements in Rust are accessed by reference by default to prevent ownership transfer unless explicitly requested.
• println!("{}", number);: Inside the loop, this line prints each element of the array using the "println!" macro. The '{}' is a placeholder for the 'number' variable, which represents the current element being iterated over.

Rust Code Editor:

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