Rust Vector Concatenation Guide

Rust Vectors: Exercise-8 with Solution

Write a Rust program to create two vectors: one with integers 1 to 5 and another with integers 6 to 10. Concatenate the two vectors and print the resulting vector.

Sample Solution:

Rust Code:

// Define the main function, the entry point of the program
fn main() {
    // Create the first vector with integers 1 to 5
    let vec1: Vec<i32> = (1..=5).collect(); // Use the range and collect method to create the vector

    // Create the second vector with integers 6 to 10
    let vec2: Vec<i32> = (6..=10).collect(); // Use the range and collect method to create the vector

    // Concatenate vec1 and vec2 into a new vector
    let concatenated_vec = [vec1, vec2].concat(); // Use the concat method for slices

    // Print the resulting concatenated vector
    println!("Concatenated Vector: {:?}", concatenated_vec);
}

Output:

Concatenated Vector: [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]

Explanation:

Here is a brief explanation of the above Rust code:

• The main function (fn main()) is defined as the starting point of the Rust program.
• Two vectors, 'vec1' and 'vec2', are created using the range syntax (1..=5) and (6..=10) respectively, which are then collected into vectors using the ".collect()" method. The type Vec<i32> explicitly states that these vectors contain 32-bit integers.
• The 'concatenated_vec' is created by concatenating 'vec1' and 'vec2' using the ".concat()" method. The [vec1, vec2] is a slice of vectors that are concatenated into a single vector. This operation does not modify 'vec1' or 'vec2'; instead, it creates a new vector that contains all the elements of 'vec1' followed by all the elements of 'vec2'.
• Finally, the concatenated vector is printed to the console using the "println!" macro with {:?} placeholder for debug formatting, which displays the vector's contents.

Rust Code Editor:

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